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likoan [24]
2 years ago
6

Helppppp please 100 points and ill give brainliest!!!

Mathematics
2 answers:
Arturiano [62]2 years ago
7 0
F(x)=4x .............
krok68 [10]2 years ago
4 0

Answer:

f(x)=4x

Step-by-step explanation:

Let's look at the progression of f(x) values as the x value goes up. The x value goes up in steps of 1, but the f(x) value goes up in steps of 4. This means that the f(x) value grows 4 times faster than the x value. Comparing them side by side, you can see that each f(x) value is indeed 4 times larger than the corresponding x value. Therefore, the descriptive function is f(x)=4x.

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Express 0.96 as an percent
enyata [817]

Answer:

96%

Step-by-step explanation:

0.96 × 100/100

(0.96 × 100)× 1/100 = 96/100

percentage = 96%

6 0
3 years ago
Read 2 more answers
4. Bobbie scores m marks in a test. <br> Georgia scores three times as many marks as Bobbie.
xxTIMURxx [149]

Marks of Bobbie = x

Then, marks of Georgia

= 3 times marks of Bobbie

= 3 times m

= 3 × m

= 3m

6 0
3 years ago
Graph a line parallel to y-2x+1 and has a y-intercept of (0,5))
Debora [2.8K]

your answer is x = 6

desmos

7 0
3 years ago
Which equation would give the graph below? (photo)
emmasim [6.3K]

Answer:

C

Step-by-step explanation:

Y= 4^2 - 5 x 4 + 4 = 0

5 0
3 years ago
The following probability distributions of job satisfaction scores for a sample of information systems (IS) senior executives an
Mashcka [7]

Answer:

Step-by-step explanation:

To calculate ;

1) the expected value of the job satisfaction score for senior executives ;

expected value = Summation (Px)

= 1 x 0.05 + 2 x 0.09 + 3 x 0.03 + 4 x 0.42 + 5 x 0.41

= 4.05

2) the expected value of the job satisfaction score for middle managers;

= 1 x 0.04 + 2 x 0.10 + 3 x 0.12 + 4 x 0.46 + 5 x 0.28

= 3.84

c) the variance of job satisfaction scores for executives and middle managers (to 2 decimals).

Executives ; Variance = Summation(PX^2 - Summation(PX)^2

i) For Executive Managers = 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2 = 1.246 = 1.25

ii) for middle managers ; 1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 = 1.134 = 1.13

d) the standard deviation of job satisfaction scores for both probability distributions (to 2 decimals). Executives, Middle managers;

For Executives = square root [ 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2] = 1.12

For Middle Managers ; Square root [1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 ] = 1.06

e) from the values gotten for the variance of both executive and middle managers, the variance of the former is more than that of the latter as such higher satisfaction with the executive managers.

5 0
3 years ago
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