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fgiga [73]
3 years ago
9

Need help with this one​

Mathematics
2 answers:
Aloiza [94]3 years ago
7 0

Answer:

At x intercept, x = 0

2.8(0)+5.7y+5.8=0

y=-5.8/5.7

=-1.02

At y intercept, y=0

2.8x+5.7(0)+5.8=0

x=-5.8/2.8

=-2.07

Ann [662]3 years ago
3 0

Answer:

X ans y intercepts are

xintercept (s) : (-2.0,0) <em>you can roud if necessary </em>

y intercept(s) : (0,-1.01754385) <em>you can round if nessecary </em>

Step-by-step explanation:

to find the x and y intercepts simply plug in o to replace x then when you solve for x plug in xto solve for y

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The correct option is D.

i.e.

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The correct graph is shown in attached figure.

Step-by-step explanation:

Considering the function

f\left(x\right)=\frac{1}{x\left(x+4\right)}

\mathrm{Domain\:of\:}\:\frac{1}{x\left(x+4\right)}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x

\mathrm{Range\:of\:}\frac{1}{x\left(x+4\right)}:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:-\frac{1}{4}\quad \mathrm{or}\quad \:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-\frac{1}{4}]\cup \left(0,\:\infty \:\right)\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:\frac{1}{x\left(x+4\right)}:\quad \mathrm{None}

\mathrm{Extreme\:Points\:of}\:\frac{1}{x\left(x+4\right)}:\quad \mathrm{Maximum}\left(-2,\:-\frac{1}{4}\right)

So, the correct graph is shown in attached figure.

Therefore, the correct option is D.

i.e.

f\left(x\right)=\frac{1}{x\left(x+4\right)} is the correct option.

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