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EleoNora [17]
4 years ago
14

Both 2 and 5 are common factors of a number. The number in between 101 and 118. What is the number? Give a reason for your answe

r.
Mathematics
1 answer:
Deffense [45]4 years ago
3 0
110
2 and 5 are prime and thus share no common factors. The lowest common multiple of 2 and 5 is therefore 2 x 5 = 10. 

Your answer must be a multiple of 10 and there is only one answer in that range that fits. 

Double-check: 
110 / 2 = 55 r. 0 
110 / 5 = 22 r. 0 

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1.35764501988

Step-by-step explanation:

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Which of the following is the complete factorization of 10x - 3 - 3x2? -(3x + 1)(x - 3) -(3x - 1)(x - 3) (3x - 1)(x + 3)
qaws [65]

Answer:

=-\left(3x-1\right)\left(x-3\right)

Step-by-step explanation:

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\mathrm{Factor\:out\:common\:term\:}x\\=x\left(3x-1\right)\\\mathrm{Factor\:out\:}-3\mathrm{\:from\:}-9x+3\mathrm{:\quad }-3\left(3x-1\right)\\-9x+3\\\mathrm{Rewrite\:}9\mathrm{\:as\:}3\cdot \:3\\=-3\cdot \:3x+3\\\mathrm{Factor\:out\:common\:term\:}-3\\=-3\left(3x-1\right)\\=x\left(3x-1\right)-3\left(3x-1\right)\\\mathrm{Factor\:out\:common\:term\:}3x-1\\=\left(3x-1\right)\left(x-3\right)\\=-\left(3x-1\right)\left(x-3\right)

5 0
4 years ago
Read 2 more answers
I need help ASAP! It's urgent.. PLISSSSS​
natali 33 [55]

Answer:

a) 6 mins

b) 70km/h

c) t= 45

Step-by-step explanation:

a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km

Duration

= 16 -10

= 6 minutes

b) Average speed

= total distance ÷ total time

Total time

= 24min

= (24÷60) hr

= 0.4 h

Average speed

= 28 ÷0.4

= 70 km/h

c) Average speed= total distance/ total time

Average speed

= 80km/h

= (80÷60) km/min

= 1⅓ km/min

1⅓= 28 ÷(t -24)

<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>

\frac{4}{3}(t -24)= 28

\frac{4}{3}t - 32= 28

\frac{4}{3}t= 32 +28

\frac{4}{3}t= 60

t= 6 0\div  \frac{4}{3}

t= 45

*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.

Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)

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4 years ago
When dividing each of the numbers $$3759$$ and $$4139$$ by some positive integer number, the remainder happened to be equal to $
Sedaia [141]

Answer:

The smallest possible value of the divisor is 19

Step-by-step explanation:

The given numbers for division are;

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Let x represent the number

Therefore, we have;

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The factors of 3743 obtained from an online resource are 1, 19, 197, 3759

The factors of 4123 obtained from an online resource are 1, 7, 19, 31, 133, 217, 589, 4123

The common factors of 3743 and 4123 are 1, 19

Given that x > 16, we have, x = 19

Therefore, the smallest possible value that will divide both 3759 and 4139 whereby the remainder is 16 = 19

3 0
3 years ago
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