Question

A soccer ball is kicked upward from a hill and then falls to the ground. The height, in feet, of the ball after t sec is modeled by the function h(t) = –16t2 + 26t +12. What is the initial height of the ball?

Answer 1

Answer: The initial height of the ball is 12 feet.

Step-by-step explanation:

We have the function $h(t)=-16t^2+26t+12$, which models the height (in feet) of the ball after $t$ seconds.

Then, as the height is in function of the time, we know that the ball is in the initial height when:

 $t=0$

So, to find the initial height, you need to substitute $t=0$ into the function:

$h(0)=-16(0)^2+26(0)+12\\\\h(0)=0+0+12\\\\h(0)=12$

Therefore, the initial height of the ball is 12 feet.

Answer 2

Answer:

answer is 12 feet c

Step-by-step explanation: