The formula for the average value of a function is
where b is the upper bound and a is the lower. For us, this formula will be filled in accordingly.
. We will integrate that now:
![\frac{1}{2}[ \frac{2x^3}{3}+3x]](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%5B%20%5Cfrac%7B2x%5E3%7D%7B3%7D%2B3x%5D%20%20)
from 0 to 2. Filling in our upper and lower bounds we have
![\frac{1}{2}[( \frac{2(2^3)}{3}+3(2))-0]](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%5B%28%20%5Cfrac%7B2%282%5E3%29%7D%7B3%7D%2B3%282%29%29-0%5D%20%20)
which simplifies to
and
which is 17/3 or 5.667
<span>✡ Answer: 9000 </span><span>✡
- - Solve:
If your 3 numbers to the right (in this problem its 3) are 499 or less, you round down, if its 500 or up, you round up.
In this case, round up.
- - Solve furthermore:
9000
</span>
✡Hope this helps<span>✡</span>
Answer: x = 5
Step-by-step explanation:
To find the mean:
Take <span>3 4 5 3 4 5 6 5 4 3 2 3 4 5 6 4 8 4 3 2 and add them all together
=83
Now you divide 83 by the number of terms in the sample set, which is 20.
83/20 = 4.15
For rounding to the nearest tenth, look at the hundredths space, which is 5. Since it is 5 or higher, round the tenths up one.
final answer= 4.2 </span><span />
