Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
<h2>A)</h2>
<h2>B)</h2><h3>Since we only have 75 tickets to sell, the domain is:</h3><h2>t ε [ 0 , 75 ]</h2>
<h2>Range: (extra)</h2><h2>m ε [ 0 , 225 ] </h2>
Answer:
6 times the sum of a number and 12 is 114. The number is 17
Step-by-step explanation:
6 x 17 + 12= 114
Answer:
26:26
Step-by-step explanation:
I hope I've helped :)
Answer:
The amount of sale is approximately 5714.
Step-by-step explanation:
Let x be the sales made that will result to the same salary and let y be the same weekly salary.
We can represent both salaries as follows:
300 + 0.04x = y
100 + 0.075x = y
Subtracting the second equation from the first, we have:
200 – 0.035x = 0
0.035x= 200
x = 200/0.035
x ≈ 5714.
Therefore, the amount of sale is approximately 5714.
