In the game Singularity, broken objects can be restored to their original condition by reversing time. This is an example of whi
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Answer:
// class definition of MethodPractice
public class MethodPractice {
// main method that begin program execution
public static void main(String args[]) {
// call to the planParty2 method is done using some parameter
// and the return value is displayed
System.out.println("The number of p-packs needed is: " + planParty2(9, 14, 6));
System.out.println("The number of p-packs needed is: " + planParty2(4, 6, 3));
System.out.println("The number of p-packs needed is: " + planParty2(4, 6, 4));
}
// planParty2 method with 3 parameters and it return an integer
// the calculation needed to get the required pack is done here
public static int planParty2(int f, int c, int p){
// the party owner is added to list of friend
// and the value is assigned to totalPeople
int totalPeople = f + 1;
// the totalPeople times the can drink
// is assigned to totalDrinkNeeded
int totalDrinkNeeded = totalPeople * c;
// number of packs required is declared
int numberOfPacks;
// if the totalDrinkNeeded contains exact multiple of a pack
// we return the numberOfPack by dividing totalDrinkNeeded with p
if (totalDrinkNeeded % p == 0){
return numberOfPacks = totalDrinkNeeded / p;
}
// else we compute if the totalDrinkNeeded is not a multiple of a pack
// first we get the remainder when the totalDrinkNeeded is divided with p
// then the needed can is computed by subtracting remainder from p
// the neededCan is added to totalDrinkNeeded, then divided with p
// and assigned to numberOfPacks
// numberOfPacks is returned.
else {
int remainder = totalDrinkNeeded % p;
int neededCan = p - remainder;
numberOfPacks = (totalDrinkNeeded + neededCan) / p;
return numberOfPacks;
}
}
}
Explanation:
Image showing the detailed question is attached.
The program is written in Java and is well commented. A sample image of program output when it is executed is attached.
