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chubhunter [2.5K]
2 years ago
7

Pls answer i will give 20 points

Computers and Technology
1 answer:
Misha Larkins [42]2 years ago
4 0

Answer:

Penicilium roqueforti

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When an Ethernet NIC has been configured by the OS to use half-duplex, the transmit pair of the twisted-pair cable usestransmiss
zzz [600]

Answer:

C

Explanation:

When an Ethernet NIC has been configured by the OS to use half-duplex, the transmit pair of the cable uses SIMPLEX transmissions, the receive pair in the SIMPLEX transmissions, and the twisted pair cable uses HALF-DUPLEX transmissions.

Cheers

7 0
3 years ago
Define a class named ComparableSquare that extends Square (defined above) and implements Comparable. Implement the compareTo met
Alexxx [7]

Answer:

/*********************************************************************************

* (The ComparableCircle class) Define a class named ComparableCircle that        *

* extends Circle and implements Comparable. Draw the UML diagram and implement   *

* the compareTo method to compare the circles on the basis of area. Write a test *

* class to find the larger of two instances of ComparableCircle objects.         *

*********************************************************************************/

public class Exercise_13_06 {

/** Main method */

public static void main(String[] args) {

 // Create two instances of ComparableCircle objects

 ComparableCircle comparableCircle1 = new ComparableCircle(12.5);

 ComparableCircle comparableCircle2 = new ComparableCircle(18.3);

 // Display comparableCircles

 System.out.println("\nComparableCircle1:");

 System.out.println(comparableCircle1);

 System.out.println("\nComparableCircle2:");

 System.out.println(comparableCircle2);

 // Find and display the larger of the two ComparableCircle objects

 System.out.println((comparableCircle1.compareTo(comparableCircle2) == 1  

  ? "\nComparableCircle1 " : "\nComparableCircle2 ") +  

  "is the larger of the two Circles");

}

}

3 0
3 years ago
A computer hard disk starts from rest, then speeds up with an angular acceleration of 190 rad/s2 until it reaches its final angu
Nataly_w [17]
The first thing we are going to do is find the equation of motion:
 ωf = ωi + αt
 θ = ωi*t + 1/2αt^2
 Where:
 ωf = final angular velocity
 ωi = initial angular velocity
 α = Angular acceleration
 θ = Revolutions.
 t = time.
 We have then:
 ωf = (7200) * ((2 * pi) / 60) = 753.60 rad / s
 ωi = 0
 α = 190 rad / s2
 Clearing t:
 753.60 = 0 + 190*t
 t = 753.60 / 190
 t = 3.97 s
 Then, replacing the time:
 θ1 = 0 + (1/2) * (190) * (3.97) ^ 2
 θ1 = 1494.51 rad
 For (10-3.97) s:
 θ2 = ωf * t
 θ2 = (753.60 rad / s) * (10-3.97) s
 θ2 = 4544,208 rad
 Number of final revolutions:
 θ1 + θ2 = (1494.51 rad + 4544.208 rad) * (180 / π)
 θ1 + θ2 = 961.57 rev
 Answer:
 the disk has made 961.57 rev 10.0 s after it starts up
3 0
3 years ago
Read 2 more answers
What is the name of the mvost powerful battery
sergij07 [2.7K]
Optima battery because it is stronger than a factory battery
6 0
3 years ago
A company uses DHCP servers to dynamically assign IPv4 addresses to workstations. The address lease duration is set as 5 days. A
nikitadnepr [17]

Answer:

FF-FF-FF-FF-FF-FF and 255.255.255.255

Explanation:

FF-FF-FF-FF-FF-FF can be defined as the layer 2 address broadcast which is often used on ethernet frames as well as help to broadcast all equipment due to the fact broadcast is made possible through Ethernet networks in which the Frames are addressed to reach every computer system on a given LAN segment as far as they are addressed to MAC address FF:FF:FF:FF:FF:FF.

255.255. 255.255 can be seen as the layer 3 address which help to address the exact same hosts because it enables the broadcast address of the zero network which is the local network due to the fact that the IP broadcasts are often used by BOOTP and DHCP clients to find and send requests to their respective servers in which a message sent to a broadcast address may be received by all network-attached hosts.

Therefore the Layer 2 and Layer 3 destination addresses which the message contain are FF-FF-FF-FF-FF-FF and 255.255.255.255

7 0
3 years ago
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