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nata0808 [166]
2 years ago
14

Sec^2 (x/2)=2/1+cosx pls pls pls help

Mathematics
1 answer:
MAVERICK [17]2 years ago
8 0

Step-by-step explanation:

hiiiiiii. ...........................,..

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What is the surface area of 120 x 110 x 4
Rina8888 [55]

surface area is the area of all the faces on a shape so to speak.

2(120 x 110)=26,400

2(120 x 4)=960

2(110 x 4)=880

880+960+26,400=28,240

Surface area = 28,240

5 0
3 years ago
Please help me!
ladessa [460]
I’ve never done a tape diagram before (so this might be wrong). But I think it’s:

6t=9

If this is correct, I hope it helps :)
3 0
3 years ago
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Can you guys help me on the number 2 I’m really stuck
JulsSmile [24]

Answer:

we have to see question 1 to help with number two

5 0
3 years ago
Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3
Maru [420]

Answer:

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

Step-by-step explanation:

The geometric progression is:

9, 3 \sqrt{3}, 3...

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}

That is the common ratio.

Geometric progression is given generally as:

a_n = ar^{(n - 1)}

where a = first term

r = common ratio

a_n = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

5 0
3 years ago
Is there a way to quickly find a function if you have a handful of ordered pairs?
Scilla [17]
Yeah. You basically have to look at every x value and see if for every x value, is there ONLY one y-value. So in your example, it is a function because every x value has only one y value. Let’s say you had (1,3) and (1,5). That would not be a function because the x value of 1 has TWO y values (3 and 5), therefore it is not a function.

That’s how you can easily spot if something is a function by just looking at a handful of ordered pairs. I hope this makes sense.
5 0
3 years ago
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