Let
be the length of the rectangle and
be the width. In the problem it is given that
. It is also given that the area
. Substituting in the length in terms of width, we have
. Using the zero product property,
. Solving these we get the width
. However, it doesn't make sense for the width to be negative, so the width must be
. From that we can tell the length
.
2/4
6/12
4/8
8/16
9/18
different factions but the same value.
Volume of the cube with side 4p = 4p x 4p x 4p = 64p³
Volume of the cube with side 2q² = 2q² x 2q² x 2q² = 8q⁶
Total Volume = 64p³ + 8q⁶
Total Volume = (4p)³ + (2q²)³
Total Volume = (4p + 2q²)( ( 4p)² - (4p)(2q²) + (2q²)²)
Total Volume = (4p + 2q²)( 16p² - 8pq² + 4q⁴)
Answer: (4p + 2q²)( 16p² - 8pq² + 4q⁴)
(-1,9) because Y is always the second number and -3*-1=3 so 9=3+6 basically :)
Answer:
Area
Step-by-step explanation:
If you are paving the parking lot, you would need every sqaure inch of the parking lot, not only the outside (which is what the perimeter is)
