Megan will count more because there are 10 ones in 10, but there are only 4 fives in 20.
Answer:the price of one child ticket is $8
the price of one adult ticket is $12
Step-by-step explanation:
Let x represent the price of one child ticket.
Let y represent the price of one adult ticket.
First tour is 4 child tickets and 8 adult tickets for 128 dollars. This means that
4x + 8y = 128 - - - - - - - - - - 1
Second tour is 6 adult tickets for 72 dollars. This means that
6y = 72
y = 72/6 = $12
Substituting y = 12 into equation 1, it becomes
4x + 8 × 12= 128
4x + 96 = 128
4x = 128 - 96
4x = 32
x = 32/4 = $8
Step-by-step explanation:
- 5+<em>4</em>=9
- 9+<em>5</em><em>=</em>14
- 14+<em>6</em><em>=</em>20
- 20+<em>7</em><em>=</em><u>2</u><u>7</u>
- 27+<em>8</em><em>=</em>35
So The sequence is 5,9,14,20,<u>2</u><u>7</u><u>,</u>35
Solution:
<h3>(D) nonexistent</h3>
lim <u>cos x + sin (2x) + 1 </u> is =0
x—> π x²+π²
<h3>Step by step explaination : </h3>
Plug in the value x = π :
<u>cos </u><u>π</u><u> + sin (2</u><u>π</u><u>) + 1</u> is
π²+π²
Last ,Simplify <u>cos π + sin (2π) + 1</u> is
π²+π²
<h3 /><h3>
= 0</h3>
