A. True
B. False
C. False
D. False
E. True
B. Quadrant II contains ordered pairs of the form (negative number, positive number)
C. (-6,0) is located on the x-axis
D. The origin is not located on any of the quadrant. It’s in the center
Given:
The expression is
To find:
The product of prime polynomials which is equivalent to the given expression.
Solution:
We have,
Taking out the common factors, we get
It can be written as
![[\because a^3-b^3=(a-b)(a^2+ab+b^2)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E3-b%5E3%3D%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29%5D)
Therefore, the correct option is B.
Step-by-step explanation:
see the photo for explanation
To solve/simplify this all you have to do is group like terms (the x^2's with each other, the x's with each other, and the normal numbers, -8)
14x^2-8+5x-6x^2+2x
group the x^2 (add 14x^2 to -6x^2)
8x^2-8+5x+2x
group the x's together (add 5x and 2x together)
8x^2+7x-8
Your answer will be d) 8x^2+7x-8
