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Free_Kalibri [48]
3 years ago
7

Calculate.

}" alt="\sqrt{(-4.5)^{4}}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
ElenaW [278]3 years ago
5 0

Answer:

Step-by-step explanation:

\sqrt{(-4.5)^{4}}=\sqrt{(-4.5)*(-4.5)*(-4.5)*(-4.5)}\\\\= (-4.5) * (-4.5)\\\\= 20.25

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Can you help me Thank you
Alexus [3.1K]
It’s 21 , good luck!!!!
7 0
3 years ago
Read 2 more answers
For the functions f(x) = 2x − 6 and g(x) = 5x + 1, which composition produces the greatest output?
kotegsom [21]

Answer:

g(x) = 5x + 1

Step-by-step explanation:

Given data

We have the following expressions to work with

f(x) = 2x − 6 and

g(x) = 5x + 1

say the value of x = 3

let us put x into the two expressions above and compare the output

f(x) = 2*3 − 6= 6-6= 0

g(x) = 5*3 + 1= 15+1= 16

Hence the second function has the greatest output

4 0
3 years ago
The youth group is going on a trip to the state fair. The trip costs $63. Included in that price is $13 for a concert ticket and
forsale [732]

Ok,

The total is 63$:

= 63

It shows us one of the numbers for the equation, 13

+ 13 = 63

Two passes together plus the thirteen equals the total of 63$

the price of the pass is unknown, so we can use a variable to figure it out:

2x + 13 = 63

Now we solve

First subtract 13 from both sides:

2x + 13 - 13 = 63 - 13

Then divide both sides by 2:

2x ÷ 2 = 50 ÷ 2

Now we get our answer:

x = 25

3 0
4 years ago
Read 2 more answers
Which graph represents the function f (x) = StartFraction 2 Over x minus 1 EndFraction + 4?
Pepsi [2]

Answer:

On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4

Step-by-step explanation:

The given function is presented as follows;

f(x) = \dfrac{2}{x - 1} + 4

From the given function, we have;

When x = 1, the denominator of the fraction, \dfrac{2}{x - 1}, which is (x - 1) = 0, and the function becomes, \dfrac{2}{1 - 1} + 4 = \dfrac{2}{0} + 4 = \infty + 4 = \infty therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote

Also we have that in the given function, as <em>x</em> increases, the fraction \dfrac{2}{x - 1} tends to 0, therefore as x increases, we have;

\lim_  {x \to \infty}  \dfrac{2}{(x - 1)} \to 0, and \  \dfrac{2}{(x - 1)}  + 4 \to 4

Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1

When -∞ < x < 1, we also have that as <em>x</em> becomes more negative, f(x) → 4. When x = 0, \dfrac{2}{0 - 1} + 4 = 2. When <em>x</em> approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left

Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.

5 0
3 years ago
What goes in the blank boxes
noname [10]

Answer:

Everything

Step-by-step explanation:

We can keep every things in the blank boxes.

7 0
3 years ago
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