Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
a(7)=3645
Step-by-step explanation:
you have :
f(1) =a= 5
and from recursive rule: f(n) = r · f(n − 1) and f(n) = 3 · f(n − 1)
So r=3
then
a(n)=a*r^(n-1)
a(7)=5*3^(7-1)
a(7)=5*3^6=3645
<em>hope this helps</em>
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Answer:
i need more information like what is the length width etc.
Step-by-step explanation:
4, 11.6, 50, 23, 20.1, 19, 29, 12.7, 8, 23, 57.5 The min= The max- 015 Q2 Q3 The range The interquartile range
earnstyle [38]
Ty for points ahaha
No jk lol I think it’s 12.7
Answer:
82%
Step-by-step explanation:
0.82x100=82
=82%
Hope this helps
