Given:
In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.
To find:
The measure of angle P.
Solution:
According to the Law of Cosines:
Using Law of Cosines in triangle OPQ, we get
On further simplification, we get
Therefore, the measure of angle P is 79 degrees.
The answer would probably be 18 degrees below normal because the absolute values of the rest are 8 not 18 which is the absolute value of 18 degrees below normal.
(2x²<span> + 3x - 4) + (8 - 3x) + (-5x</span>²<span> + 2)
= </span> 2x² + 3x - 4 + 8 - 3x - 5x² + 2
= -3x² + 6
= 3(-x² + 2)
Answer:
y=-2x-12
Step-by-step explanation:
first, putt 3x-6y=2 in standard form:
subtract 3x from both sides: -6y=-3x+2
divide both sides by -6 to isolate y: y=1/2x-1/3
if the other line is perpendicular to this, you must find the slope by finding the opposite reciprocal of 1/2x: -2
now we have 2 points a slope, so we use the point-slope formula: y-y1=m(x-x1)
y+2=-2(x+5)
Use the distributive property: y+2=-2x-10
subtract 2 for both sides to isolate y: y=-2x-12
= 6 feet