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2 years ago

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Ar+1

1 answer:

irinina [24]2 years ago

6 0

Answer:

$563 \frac{22 \frac{ 11\frac{2222}{ffggyy2} }{?2} 22}{2?}$

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3x+6=21 what is the value of x

Kamila [148]

Answer:

$3x + 6 = 21 \\ 3x = 21 - 6 \\ 3x = 15 \\ x = \frac{15}{3} \\ x = 5$

8 0

3 years ago

Read 2 more answers

PLz answer i really need this

mart [117]

A is the correct answer darlin

6 0

3 years ago

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For a recently released movie, the function y = 119.67(0.61)x models the revenue earned, y, in millions of dollars each week, x,

Marina CMI [18]

Given:
Function y = 119.67(0.61)x

x = week 3.

F(3) = 119.67(0.61)(3)
F(3) = 119.67*1.83
F(3) = 218.9961

x = week 5

F(5) = 119.67(0.61)(5)
F(5) = 119.67 * 3.05
F(5) = 364.9935

4 0

4 years ago

The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the common difference of the sequence?

sertanlavr [38]

Answer:

<h2> C) 4</h2>

Step-by-step explanation:

The nth term of arithmetic sequence is $a_n=a_1+d(n-1)$

So:

$a_{15}=a_1+d(15-1)\\\\53=-3+14d\\\\56=14d\\\\d=\dfrac{56}{14}=4$

5 0

3 years ago

△ABC is a right triangle with right angle C. Side AC¯¯¯¯¯¯¯¯ is 6 units longer than side BC¯¯¯¯¯¯¯¯. If the hypotenuse has lengt

Vladimir [108]

Given:

In △ABC is a right angle triangle.

AC is 6 units longer than side BC.

$Hypotenuse=2\sqrt{17}$

To find:

The length of AC.

Solution:

Let the length of BC be x.

So, Length of AC = x+6

According to the Pythagoras theorem, in a right angle triangle

$Hypotenuse^2=Base^2+Perpendicualar^2$

△ABC is a right angle triangle and AC is hypotenuse, so

$(2\sqrt{17})^2=(x)^2+(x+6)^2$

$68=x^2+x^2+12x+36$ $[\because (a+b)^2=a^2+2ab+b^2]$

Subtract 68 from both sides.

$0=2x^2+12x+36-68$

$0=2x^2+12x-32$

$0=2(x^2+6x-16)$

Divide both sides by 2.

$x^2+6x-16=0$

Splitting the middle term, we get

$x^2+8x-2x-16=0$

$x(x+8)-2(x+8)=0$

$(x+8)(x-2)=0$

$x=-8,2$

Side cannot be negative, so x=2 only.

Now,

$AC=x+6$

$AC=2+6$

$AC=8$

Therefore, the length of AC is 8 units.

6 0

3 years ago