I think for this item, the rate at which the gasoline was consumed is to be calculated. To determine the distance that Stanley's car had traveled, we subtract 840 miles from 1,200 miles. That will give us an answer of 360 miles. Dividing this by 12 gallons will give us an answer of 30 miles/gal.
Answer : p(only z)=0.40 and p(only u)=0.08
Explanation :
We have given that ,
p(u)=0.22,
p(z∪u)=0.62,
p(z)=0.54
By using probability rule of union of 2 events, we have,
p(z)+p(u)-p(z∩u)=p(z∪u)
⇒0.54+0.22-p(z∩u)=0.62
⇒0.76-p(z∩u)=0.62
⇒(-)p(z∩u)=0.62-0.76
⇒(-)p(z∩u)= (-)0.14
⇒p(z∩u)=0.14
Now,
p(only z)=p(z)-p(z∩u)
=0.54-0.14
=0.40
and,
p(only u)=p(u)-p(z∩u)
=0.22-0.14
=0.08
∴ Each probability will be
p(only z)=0.40
p(only u)=0.08
Given that
(2/x)+(3/y) = 13--------(1)
(5/x)-(4/y) = -2 -------(2)
Put 1/x = a and 1/y = b then
2a + 3b = 13 ----------(3)
On multiplying with 5 then
10a +15 b = 65 -------(4)
and
5a -4b= -2 ----------(5)
On multiplying with 2 then
10 a - 8b = -4 -------(6)
On Subtracting (6) from (4) then
10a + 15b = 65
10a - 8b = -4
(-)
_____________
0 + 23 b = 69
______________
⇛ 23b = 69
⇛ b = 69/23
⇛ b =3
On Substituting the value of b in (5)
5a -4b= -2
⇛ 5a -4(3) = -2
⇛ 5a -12 = -2
⇛ 5a = -2+12
⇛ 5a = 10
⇛ a = 10/5
⇛ a = 2
Now we have
a = 2
⇛1/x = 2
⇛ x = 1/2
and
b = 3
⇛1/y = 3
⇛ y = 1/3
<u>Answer :-</u>The solution for the given problem is (1/2,1/3)
<u>Check</u>: If x = 1/2 and y = 1/3 then
LHS = (2/x)+(3/y)
= 2/(1/2)+3/(1/3)
= (2×2)+(3×3)
= 4+9
= 13
= RHS
LHS=RHS is true
and
LHS=(5/x)-(4/y)
⇛ 5/(1/2)- 4/(1/3)
⇛(5×2)-(4×3)
⇛ 10-12
⇛ -2
⇛RHS
LHS = RHS is true
236
2 hundreds + 3 tens + 6 ones or
200 + 30 + 6
236
Answer:
17
Step-by-step explanation:
