Can someone plz help me, I need answers asap

The mean is 10,

The median is 10,

And there is no mode.

The mean of a set of numbers is the sum divided by the number of terms,

7+15+12+6+10=50

There are 5 numbers in the set,

50/5=10.
10 is the mean.

Arrange the data in an ascending order and the median is the middle value. If the number of values is an even number, the median will be the average of the two middle numbers,

6, 7, 10, 12, 15,

10 is in the middle so it is the median.

The mode is the element that occurs most in the data set. In this case, all elements occur only once, so there is no mode.

Just so you don’t confuse the data with the group sets,

The actual data set is 7, 15, 12, 6, and 10

This data paired with score column or group set means that,

10 people got a score of 1-10
6 people got a score of 11-20
12 people got a score of 21-30
15 people got a score of 31-40
And 7 people got a score of 41-50 :)

4 0

2 years ago

A researcher reports a 98% confidence interval for the proportion of Drosophila in a population with mutation Adh-F to be [0.34,

Fantom [35]

Answer:

$0.34 \leq p \leq 0.38$

For this case we can conclude that with 98% of confidence the true proportion of Drosophila in a population would be between 0.34 and 0.38.

But that doesn't means that we have 98% of PROBABILITY that the true proportion would be between 0.34 and 0.38, because we are constructing a confidence interval with sample data and we can't analyze this using probability.

Then the best answer is:

2. False

Step-by-step explanation:

For this case we have a confidence interval for the proportion of Drosophila in a population with mutation Adh-F to be given by: