System of Linear Equations entered :
[1] y - 2x/3 = -1
[2] y + x = 4
// To remove fractions, multiply equations by their respective LCD
Multiply equation [1] by 3
// Equations now take the shape:
[1] 3y - 2x = -3
[2] y + x = 4
Graphic Representation of the Equations :
-2x + 3y = -3 x + y = 4
Solve by Substitution :
// Solve equation [2] for the variable x
[2] x = -y + 4
// Plug this in for variable x in equation [1]
[1] 3y - 2•(-y +4) = -3
[1] 5y = 5
// Solve equation [1] for the variable y
[1] 5y = 5
[1] y = 1
// By now we know this much :
y = 1
x = -y+4
// Use the y value to solve for x
x = -(1)+4 = 3
I hope this help you
Answer:
the answers are all bold below
Step-by-step explanation:
Triangle ABC is an equilateral triangle with side lengths labeled a, b, and c.
Triangle A B C is an equilateral triangle. The length of side A B is c, the length of B C is a, and the length of A C is b.
Trigonometric area formula: Area = One-half a b sine (C)
Which expressions represent the area of triangle ABC? Select three options.
a c sine (60 degrees)
One-half b c sine (60 degrees)
One-half a squared sine (60 degrees)
StartFraction a squared b sine (60 degrees) Over 2 EndFraction
StartFraction a b sine (60 degrees) Over 2 EndFraction
It's C.
multiply by 3
x = 4, y = 4x3 = 12
x = 5, y = 5x3 =15
x = 6, y = 6x3 =18
