Granite that is

small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi

irina [24]

Answer:

Frequency of p $= 0.684$

Frequency of p $= 0.316$

Number of individuals with homozygous dominant (AA) $= 47$

Number of individuals with heterozygous (Aa) $= 43$

Number of individuals with homozygous recessive (aa) $= 10$

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals $(q^{2})$ is $\frac{10}{100} = 0.1$

Now, q will be

$= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316$

As per Hardy Weinberg's equation -

$p + q = 1$

Substituting the value of q in above equation, we get -

$p + 0.316 = 1p = 1 -0.316\\p = 0.684$

Now the frequency of homozygous dominant (AA) will be

$p^{2} = 0.684^{2} \\= 0.467$

Hence, out of 100 people $0.467 * 100 = 46.7 or 47$ people are homozygous dominant (AA)

Like wise out of 100 people $0.1 * 100 = 10$ people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

$p^{2} + q^{2} + 2pq = 1\\$

Substituting the values in above equation, we get -

$0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433$

So, out of 100 people $0.433 * 100 = 43.3 or 43$ people are heterozygous (Aa)

7 0

4 years ago

PLEASE HELP!! im despratte

Alex73 [517]

Answer:

Template strand = complementary strand

GCA AG = CGT TC

TTA CG = AAT GC

GAT AC = CTA TG

CGG AT = GCC TA

DNA strand = mRNA strand

CGA TT = GCU AA

GCT TA = CGA AU

GCA TC = CGU AG

TTC AT = AAG UA

It is more important for DNA replication to be exact than transcription or translation because any error that occurs during DNA replication if not repaired will become permanent and will be transferred to the next generation.

Explanation: In DNA base pairing, G pairs with C and T pairs with A. But in RNA base pairing, G pairs with C and U pairs with A. DNA contains four bases G, C, T and A while RNA contains four bases G, C, A and U.

See the attached file

5 0

3 years ago

Give any three conditions which a contract can be terminated

Sedaia [141]

Answer:

Each of the following constitutes a repudiatory breach of contract justifying termination at common law:

Explanation:

8 0

3 years ago

Read 2 more answers

Which of the following situations does diffusion not help, in our bodies?A. Oxygen entering the bloodstream.B. Food entering the

lubasha [3.4K]

Answer:

Glucose entering the intestines from the villus.This is by active transport.The latter is defined as the movement of molecules and solutes from the region of lower concentration to the region of higher concentration against the concentration gradient.

Explanation:

All the above options depends on the diffusion gradients from one higher region to another.e.g oxygen passing from high concentration from outside to lower concentration in blood stream,like wise Co2 from higher concentration from inside to outside,with passive diffusion lipids and water enter the small intestine(note amino acid and glucose,and fructose are different).

Active transport( through sodium dependent transporter) transports glucose to the intestine from the villus.This is movements against concentration gradient because,glucose molecule are concentrated in intestine,and needed by the cells, in the body.Therefore they must be transported as a fast rate inn the blood .

However the absorption by the villi is very slow,therefore active transport is needed to move these against the concentration gradient into the intestine.And finally the blood.

If this were to be moved by passive diffusion,the high concentration in the intestine will force this back into the villi

Therefore extra energy is needed by active transport for the glucose molecules to enter the intestine from the villus.

6 0

4 years ago

What is the likely effect from radiation that leads to the death of a bacterial cell?

kotegsom [21]

Answer:

A

Explanation:

because bacteria grows small till it dies

5 0

2 years ago