The new mixture exists 56.5% peanuts.
<h3>How to estimate the total number of peanuts required for the mixture?</h3>
The first batch of 9 lb of mixed nuts possesses 40% peanuts.
This means the quantity of peanuts exists:
9
40/100 = 3.6 lb
The second batch of 9 lb of mixed nuts possesses 73% peanuts.
This means the quantity of peanuts exists:
9
73/100 = 6.57 lb
The total quantity of peanuts in the mix exists
3.6 lb + 6.57 lb = 10.17 lb
There exist 9 lb + 9 lb = 18 lb of mix.
Therefore, the percent of peanuts in the mix exists:
10.17 / 18
100 = 56.5%
The new mixture exists 56.5% peanuts.
To learn more about the total quantity refer to:
brainly.com/question/18919760
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1 toy costs $3 ( $3 x 1 = $3)<span>
2 toys cost $6 ( </span> $3 x 2 = $6)<span>
3 toys cost $9 </span>( $3 x 3 = $9)
4 toys cost $12 ( $3 x 4 = $12)
answer 4 toys will cost $12
You said "He used 3/5 of it for his project " so your question"What fraction of the spool was used for his project?" you already solved dumbas and I copied and pasted your dumb question
Answer:
1/36
Step-by-step explanation:
assuming a 6-sided fair die, the probability that you roll any number from 1-6 for any one roll is 1/6,
hence
P(roll 5) = 1/6
P(roll 6) = 1/6
P( roll 5 then roll 6)
= P(roll 5) x P(roll 6)
= (1/6) (1/6)
= 1/36