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brilliants [131]
3 years ago
6

How much is 2+10.Please help me i dont knowWill give brainliest

Mathematics
2 answers:
Hitman42 [59]3 years ago
8 0

Answer: 12

Step-by-step explanation: just add 2 to 10

givi [52]3 years ago
5 0

Answer: 12

2 + 10

12

:)

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Graph a line through (2,-5) and have a slope of -4
kirill115 [55]

im sorry: In order to solve the inequality -x > 8, which of the following steps must be done?

7 0
3 years ago
The value of zlatan's house has increased by 7% his house is now valued at £749 000
quester [9]

Answer:

£642,000

Step-by-step explanation:

7% of 749,000 is 107,000

749,000-107,000=642,000

6 0
3 years ago
Fill in the table using this function rule.<br> y=25-2x
marissa [1.9K]

Answer:(1,23)(2,21)(4,17)(6,13)

Step-by-step explanation:

Plug in the x values in the graph to the function. For example plug in 2 to it and you get 25-2(2) which transfers to 25-4. 25-4 equals 21

8 0
3 years ago
A research program used a representative random sample of men and women to gauge the size of the personal network of older adult
My name is Ann [436]

Answer:

a. \mu=\bar x =14.6

b. The 95% CI for the population mean is (14.22, 14.98).

c. B. "The statement is incorrect. A correct statement would be​"One can be​ 95% confident that the true mean number of people named per person will fall in the interval computed in part b"

d. D. It does not impact the validity of the interpretation because the sampling space of the sample mean is approximately normal according to the Central Limit Theorem.

Step-by-step explanation:

a) The sample mean provides a point estimation of the population mean.

In this case, the estimation of the mean is:

\mu=\bar x =14.6

b) With the information of the sample we can estimate the

As the sample size n=2824 is big enough, we can aproximate the t-statistic with a z-statistic.

For a 95% CI, the z-value is z=1.96.

The sample standard deviation is s=10.3.

The margin of error of the confidence is then calculated as:

E=z\cdot s/\sqrt{n}=1.96*10.3/\sqrt{2824}=20.188/53.141=0.38

The lower and upper limits of the CI are:

LL=\bar x-z\cdot s/\sqrt{n}=14.6-0.38=14.22\\\\UL=\bar x+z\cdot s/\sqrt{n}=14.6+0.38=14.98

The 95% CI for the population mean is (14.22, 14.98).

c. "95% of the​ time, the true mean number of people named per person will fall in the interval computed in part b"

The right answer is:

B. "The statement is incorrect. A correct statement would be​"One can be​ 95% confident that the true mean number of people named per person will fall in the interval computed in part b"

The confidence interval gives bounds within there is certain degree of confidence that the true population mean will fall within.

It does not infer nothing about the sample means or the sampling distribution. It only takes information from a sample to estimate a interval for the population mean with certain degree of confidence.

d. It is unlikely that the personal network sizes of adults are normally distributed. In​ fact, it is likely that the distribution is highly skewed. If​ so, what​ impact, if​ any, does this have on the validity of inferences derived from the confidence​ interval?

The answer is:

D. It does not impact the validity of the interpretation because the sampling space of the sample mean is approximately normal according to the Central Limit Theorem.

The reliability of a confidence interval depends more on the sample size, not on the distribution of the population. As the sample size increases, the absolute value of the skewness and kurtosis of the sampling distribution decreases. This sample size relationship is expressed in the central limit theorem.

4 0
4 years ago
A company makes three purchases on July 5, one for $550, another for $250 and a third for $75. It returns merchandise costing $3
Andrews [41]
To find how much is due, you will add the total expenses and subtract the returned amount.  You will pay for 8/10 (1 - 2/10) of these costs.

8/10 ($550 + $250 + $75 - $35) = $672.

The amount due is $672.
8 0
3 years ago
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