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3 years ago

8

Which ordered pair is a solution to the system of linear equations?

2 answers:

enyata [817]3 years ago

5 0

2x + 3y = 6.....multiply by 3
-3x + 5y = 10...multiply by 2
-----------------
6x + 9y = 18 (result of multiplying by 3)
-6x + 10y = 20 (result of multiplying by 2)
-----------------add
19y = 38
y = 38/19
y = 2

2x + 3y = 6
2x + 3(2) = 6
2x + 6 = 6
2x = 6 - 6
2x = 0
x = 0

solution is : (0,2)

LiRa [457]3 years ago

4 0

Answer is (0,2). I have the picture above as my work. I am very sure it's right.

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To find:

A. The value of x.

B. The measure of angle RQP.

Solution:

A. We need to find the value of x.

We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.

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$5x=90-15$

$5x=75$

Divide both sides by 5.

$x=\dfrac{75}{5}$

$x=15$

Therefore, the value of x is 15.

B. We need to find the measure of angle RQP.

From the given figure, it is clear that

$m\angle RQP=(2x+3)^\circ$

Putting $x=15$ , we get

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$m\angle RQP=(30+3)^\circ$

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Anestetic [448]

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solong [7]

You probably mean either

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or

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and in the second,

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