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larisa [96]
3 years ago
8

Which ordered pair is a solution to the system of linear equations?

Mathematics
2 answers:
enyata [817]3 years ago
5 0
2x + 3y = 6.....multiply by 3
-3x + 5y = 10...multiply by 2
-----------------
6x + 9y = 18 (result of multiplying by 3)
-6x + 10y = 20 (result of multiplying by 2)
-----------------add
19y = 38
y = 38/19
y = 2

2x + 3y = 6
2x + 3(2) = 6
2x + 6 = 6
2x = 6 - 6
2x = 0
x = 0

solution is : (0,2)
LiRa [457]3 years ago
4 0
Answer is (0,2). I have the picture above as my work. I am very sure it's right.

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brilliants [131]
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9/6=1 3/6 or 1 1/2
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3 0
3 years ago
Help with at least one of these ?
Blababa [14]
5. rational number
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8 0
3 years ago
The product of 12 and k is 84.
Vesnalui [34]

Answer:

to solve this we do the oppisite of multiplication which is division

so 84 divided by 12 = 7 so that means that our mysterious k = 7

so reprhase  the sentence so  '' The product of 12 and 7 is 84

hope this helps:)

Step-by-step explanation

8 0
3 years ago
Read 2 more answers
The sign of the product of -35 and -625 is positive, negative, or zero
IRISSAK [1]

Answer:

Positive

Step-by-step explanation:

The product of two negative numbers has a positive sign, whereas the product of a positive and a negative number is negative.

Since -35 and -625 are both negative, they would have a positive sign for their product.

Hope this helps.

7 0
3 years ago
The heights in inches of orangutans Are normally distributed with a population standard deviation of 3" and an unknown populatio
CaHeK987 [17]

Answer: The 95% confidence interval is approximately (55.57, 58.43)

======================================================

Explanation:

At 95% confidence, the z critical value is about z = 1.960 which you find using a table or a calculator.

The sample size is n = 17

The sample mean is xbar = 57

The population standard deviation is sigma = 3

The lower bound of the confidence interval is

L = xbar - z*sigma/sqrt(n)

L = 57 - 1.960*3/sqrt(17)

L = 55.5738905247863

L = 55.57

The upper bound is

U = xbar + z*sigma/sqrt(n)

U = 57 + 1.960*3/sqrt(17)

U = 58.4261094752137

U = 58.43

Therefore the confidence interval (L, U) turns into (55.57, 58.43) which is approximate.

7 0
3 years ago
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