The excess reactant in the combustion of 211 g of methane in an open atmosphere is oxygen, O₂
<h3>What is a combustion reaction? </h3>
A combustion reaction is a reaction in which a substance burns in air (oxygen) to produce carbon dioxide and water.
<h3>Combustion of methane </h3>
Methane combust in air (oxygen) to produce carbon dioxide and water according to the following equation:
CH₄ + 2O₂ —> CO₂ + 2H₂O
From the question given above, we were told that 211 g of methane combust in an open atmosphere. This simply means that the amount of oxygen will be very high.
Therefore, we can conclude that oxygen will be the excess reactant since the reaction is carried out in an open atmosphere.
Learn more about stoichiometry:
brainly.com/question/14735801
<em>x</em> ² + 2<em>x</em> - 2<em>xy</em> - 2<em>y</em> + <em>y</em> ² = (<em>x</em> ² - 2<em>xy</em> + <em>y</em> ²) + 2 (<em>x</em> - <em>y</em>)
… = (<em>x</em> - <em>y</em>)² + 2 (<em>x</em> - <em>y</em>)
… = 50² + 2 × 50
… = 2600
Answer:
D. It is found in the nucleus of a cell.
Explanation:
Johannes Friedrich Miescher was a Swiss biologist and physicist born on the 13th of August, 1844 in Basel, Switzerland. Miescher was the first scientist to isolate nuclein (nucleic acid) after experimenting with white blood cells in the year, 1869.
From the experiment, Friedrich Miescher was able to identify Deoxyribonucleic Acid (DNA) as a carrier of heredity (inheritance) found in the nucleus of a cell.
Hence, the important property of Deoxyribonucleic Acid (DNA) which Friedrich Miescher discover was that, it is found in the nucleus of a cell.
