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schepotkina [342]
3 years ago
5

Challenge Three friends started savings accounts at the same time, with the same initial deposit.

Mathematics
2 answers:
Wittaler [7]3 years ago
5 0

Answer: B

Step-by-step explanation:

ez

TiliK225 [7]3 years ago
4 0

Answer:

B

Step-by-step explanation:

The values given are the change in their account balance. We can identify this by the words "Louise's account shows a total change of," and the other values are also identified as "total change of."  From here, we are able to rank the changes of values from least to greatest.

$28.69 < $56.84 < $89.12

The friend with the least change is the friend whose change in account balance was $28.69.  This is Franklin.  This logic is consistent for the other friends.

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2<br> _ x -7=11<br> 5<br> whats the answer
ZanzabumX [31]

Answer:

x=45

Step-by-step explanation:

8 0
2 years ago
Can anyone pls help me to solve question 2 f and g and pls provide me a explanation I’m with that questions for three days
zvonat [6]

Answer:

  f)  a[n] = -(-2)^n +2^n

  g)  a[n] = (1/2)((-2)^-n +2^-n)

Step-by-step explanation:

Both of these problems are solved in the same way. The characteristic equation comes from ...

  a[n] -k²·a[n-2] = 0

Using a[n] = r^n, we have ...

  r^n -k²r^(n-2) = 0

  r^(n-2)(r² -k²) = 0

  r² -k² = 0

  r = ±k

  a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q

We find p and q from the initial conditions.

__

f) k² = 4, so k = 2.

  a[0] = 0 = p + q

  a[1] = 4 = -2p +2q

Dividing the second equation by 2 and adding the first, we have ...

  2 = 2q

  q = 1

  p = -1

The solution is a[n] = -(-2)^n +2^n.

__

g) k² = 1/4, so k = 1/2.

  a[0] = 1 = p + q

  a[1] = 0 = -p/2 +q/2

Multiplying the first equation by 1/2 and adding the second, we get ...

  1/2 = q

  p = 1 -q = 1/2

Using k = 2^-1, we can write the solution as follows.

The solution is a[n] = (1/2)((-2)^-n +2^-n).

 

5 0
3 years ago
Simplify: m^2n^3 aanm^2a^2n^4
dolphi86 [110]

9514 1404 393

Answer:

  a^4·m^4·n^8

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)(a^c) = a^(b+c)

__

m^2n^3 aanm^2a^2n^4

= a^(1+1+2)·m^(2+2)·n^(3+1+4)

= a^4·m^4·n^8

3 0
3 years ago
What is midpoint 85 90?
monitta
The midpoint of 85 and 90 is 87
8 0
3 years ago
After being exposed to an incredible shrinking machine, Halley's height decreased by 108 cm over 6 seco
uysha [10]

Answer:

it would be -18

Step-by-step explanation:

because you would divide 108 by 6 and you will get -18 each second

6 0
3 years ago
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