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schepotkina [342]
3 years ago
5

Challenge Three friends started savings accounts at the same time, with the same initial deposit.

Mathematics
2 answers:
Wittaler [7]3 years ago
5 0

Answer: B

Step-by-step explanation:

ez

TiliK225 [7]3 years ago
4 0

Answer:

B

Step-by-step explanation:

The values given are the change in their account balance. We can identify this by the words "Louise's account shows a total change of," and the other values are also identified as "total change of."  From here, we are able to rank the changes of values from least to greatest.

$28.69 < $56.84 < $89.12

The friend with the least change is the friend whose change in account balance was $28.69.  This is Franklin.  This logic is consistent for the other friends.

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Can someone plz help? Only have a hour...I'll make crown the best and triple the points!!!
kykrilka [37]

Answer:

x= 3.57

Step-by-step explanation:

32 ( x + 2.5) = 114.24

32* x + 32* 2.5= 114.24

32x + 80= 114.24

        -80      -80

32x= 114.24

/ 32    /32

x= 3.57

for the part that says convince me, we can use the eqution

/= divide

8 0
3 years ago
Identify the slope and y-intercept of the line with the given equation:
miv72 [106K]
1) (solve for Y 1st)
-4y=16
y=-4
slope=0        y-inter= -4

2)(solve for X 1st)
6x=12
x=2
slope=undefined     y-inter= none
3 0
3 years ago
Read 2 more answers
Find (f ° g)(0). *
atroni [7]

Answer:

B

Step-by-step explanation:

Remark

I have to represent f(x) as plus +f(x)

I like to show this situation as +f(g(x)) which I think is much clearer.

+f(x) = 5x - 4    

Solution

+f(g(x)) = 5(g(x)) - 4  What has happened is that wherever you see an x on the right you put in g(x).

Now on the right, you put whatever g(x) is equal  to.

+f(g(x)) = 5(x^2 - 1)  - 4    

Remove the brackets.

+f(g(x)) = 5x^2 - 5 - 4

And make x = 0

+f(g(0)) = 5*0 - 5 - 4

+f(g(0)) = - 9

8 0
3 years ago
Find the value of x.<br> 128<br> (6x + 20
DENIUS [597]
What is the 128 for ?
6 0
3 years ago
Will mark the brainiest! What are the coordinates of the vertex of the graph of f(x)=−3|x−1|?
AleksAgata [21]

Answer:

well, the cheap answer is

f(x) = -3| x - 1 |  is really just  f(x) = -3| x - 1 | + 0.

now, what value of "x" makes the absolute value expression to 0?

well, let's just set it to 0 and check,

x - 1 = 0

x = 1

so if "x" ever becomes 1, the | x - 1| will turn to 0, therefore, the vertex is at   

f(x) = -3| (1) - 1 | + 0  -------------->  ( 1, 0 )

6 0
3 years ago
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