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3 years ago

Help pls??????????????????????????????????????????????????????????

Mathematics

1 answer:

rosijanka [135]3 years ago

3 0

Answer:

I would probably say independent but idk

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Alan drove from his home to the grocery store, and then, he drove to the pizza shop passing his house on the way. After eating l

ahrayia [7]

Answer:

It took him 7.5 hrs to drive home.

my bad

Step-by-step explanation:

5 0

3 years ago

experts, geniuses, aces and moderators .. need help on the attached. will give brainliest!!! find the derivative of e^x

STatiana [176]

To find the derivative, you must use the chain rule.

If u=x^3+2x:
dy/dx=(dy/du)(du/dx)
dy/du=d/du(e^u)=e^u=e^(x^3 + 2x)
du/dx =d/dx (x^3+2x) = 3x^2 + 2

So dy/dx=
e^(x^3+2x) * (3x^2+ 2)

4 0

4 years ago

Y=-2x+5 was shifted down 7 units what equation is it now

baherus [9]

Answer:

$y=-2x-2$

Step-by-step explanation:

we have

$y=-2x+5$

This is the equation of a line in slope intercept form

where

$m=-2$ ---> the slope

$b=5$ ----> the y-intercept

we know that

If the given line was shifted down 7 units, then the new y-intercept is equal to

$b=5-7=-2$

The slope of the new line will be the same that the original line, because are parallel lines

The new equation is

$y=-2x-2$

3 0

4 years ago

Pls explain your answer

jasenka [17]

Middle square area= 8x8=64
one triangle area = (8x8)/2
multiply the triangel area by four and add the square area-- (4x32)+64=192

7 0

3 years ago

There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student

Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

$\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57$

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0

4 years ago