Answer:
Machine B is the faster machine because it packs 4 cartons in an hour while the other machine takes 5 hours to pack 4 cartons. The faster machine can pack 4 cartons in an hour.
Step-by-step explanation:
9514 1404 393
Answer:
2/5, 7/15, 8/15, 3/5, 2/3
Step-by-step explanation:
If these fractions are expressed with a common denominator, that would be 3×5 = 15. Then the given fractions are 1/3 = 5/15, and 4/5 = 12/15. The numerators 5 and 12 differ by 7, so we can easily choose 5 fractions in that range:
6/15 = 2/5
7/15
8/15
9/15 = 3/5
10/15 = 2/3
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<em>Alternate solutions</em>
There is no requirement for the fractions to be written any particular way or with any particular spacing. The limits in decimal are 1/3 = 0.3333...(repeating) and 4/5 = 0.8. We could choose the decimal fractions ...
0.34, 0.40, 0.50, 0.60, 0.70
or
0.41, 0.52, 0.63, 0.74, 0.79
Hi
6*3 + (9-3)
= 18 + 3
= 21
I hope that's help !
<span>Percentage problems are simple division problems. Here, what percentage of x is y means the answer is y divided by x (times 100). Let's apply it to this question.
Divide 72.6 by 88, 72.6/88. So the answer would be 0.825 then multiply it to 100 to make it a whole. The answer would 82.5%. I hope this helps you with your problem</span>
25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
