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myrzilka [38]
2 years ago
13

(Due soon, please hurry!)

Mathematics
2 answers:
Ludmilka [50]2 years ago
8 0

Answer:

I Dont Know

Step-by-step explanation:

topjm [15]2 years ago
8 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The corresponding element in the range is ~

\boxed{11}

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

Just plug the value of element in domain in the given function ~

we get ~

  • f(x) =  \dfrac{5x - 18}{2}

  • f(8) =  \dfrac{(5 \times 8) - 18}{2}

  • f(8) =  \dfrac{40 - 18}{2}

  • f(8) =  \dfrac{22}{2}

  • f(8) = 11

hence , the corresponding element in the range is ~ 11

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24/6= 4kg/hour

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Ana Participated in each charity walk she raise $.25 and each 1/2 That she walked the first day and I walked 11 miles a second d
Tresset [83]

<em><u>Question:</u></em>

Ana participated in a charity walk. She raised $0.25 for each 1/2 mile that she walked.The first day Ana walked 11 miles.The second day, she walked 14 miles.How much money did Ana raised?

<em><u>Answer:</u></em>

Ana raised $ 12.5

<em><u>Solution:</u></em>

From given question,

First day walk = 11 miles

Second day walk = 14 miles

<em><u>Let us first calculate the total distance she walked</u></em>

Total distance = first day walk + second day walk

Total distance = 11 + 14 = 25 miles

Thus she walked for 25 miles

Given that,

<em><u>She raised $0.25 for each 1/2 mile that she walked</u></em>

\frac{1}{2} \text{ mile} = 0.25 \text{ dollars }

Therefore, for 1 mile we get,

\frac{1}{2} \times 2 \text{ mile} = 0.25 \times 2 \text{ dollars }\\\\1 \text{ mile } = 0.5 \text{ dollars }

Now calculate for 25 miles

25 \text{ mile } = 25 \times 0.5 = 12.5 \text{ dollars }

Thus she raised $ 12.5

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A bird is flying 30 feet above sea level and sees a fish 4 feet below sea level. How far will the bird travel to catch the fish
Sergeeva-Olga [200]

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Please expand the logarithmic expression: Log3(7X^3Y^2)
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sertanlavr [38]

Answer:

x=4\\\\y=6\\\\IK=47

Step-by-step explanation:

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Here tangents at J and H meet at I.

Hence\ HI=IJ\\\\y^2-10=4y+2\\\\y^2-4y-12=0\\\\y^2-6y+2y-12=0\\\\y(y-6)+2(y-6)=0\\\\(y-6)(y+2)\\\\y\ can\ not\ be\ negative\ as\ in\ that\ case\ IJ\ will\ be\ negative.\\\\Hence\ y=6\\\\IJ=4y+2=4\times 6+2=26\\\\\\\\Tangents\ at\ J\ and\ L\ meet\ at\ K.\ Use\ two\ tangent\ theorem.\\\\JK=KL\\\\5x+1=6x-3\\\\6x-5x=1+3\\\\x=4\\\\JK=5x+1=5\times 4+1=21\\\\\\IK=IJ+JK=26+21\\\\IK=47

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