Question

Selena is 6 years younger than Paul. In 15 years, Paul will be 4 times the age that Selena is now. Find their present ages.

Answer 1

Answer:

The ages of Paul and Selena are 13 and 7 years old.

Step-by-step explanation:

Age of Paul = x

Age of Selena = x -6

Age of Paul and Selena in 15 years:

x + 15 = 4 (x - 6)

x + 15 = 4x - 24

x - 4x = -24 - 15

- 3x = -39

x = 13

Paul now is 13 years old and Selena is 7 years old. In 15 years, Paul will be 28, that is 4 times the present age of Selena.

Answer 2

Their present ages :

Paul = 13

Selena = 7

Further Explanation

One variable linear equation is an equation that has a variable and the exponent number is one.

Can be stated in the form:

$\large {\boxed {\bold {ax = b}}$

or

ax + b = c,

where a, b, and c are constants, x is a variable

Whereas the two-variable linear equation is a linear equation that has 2 variables and the exponent is one

Can be stated in the form:

$\large {\boxed {\bold {ax + bx = c}}}$

x, y = variable

In the statement of the task:

• Selena is 6 years younger than Paul.

can be stated in the equation:

Selena (S) = Paul (P) -6 ⇒S = P-6 ⇒equation 1

• In 15 years, Paul will be 4 times the age that Selena is now.

The equation: 15 + P = 4S⇒equation 2

Equation 1 is substituted into equation 2 so that it becomes:

15 + P = 4 (P-6)

So the solution is:

15+P = 4P-24

15+24 = 3P

39 = 3P

P = 13

From equation 1

S = P - 6

S = 13 - 6

S = 7

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Keywords : present age, Selena, Paul

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