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Aleksandr [31]
3 years ago
9

I cant figure out the awnser9+10​

Mathematics
2 answers:
ExtremeBDS [4]3 years ago
5 0

Answer:

19

Step-by-step explanation:

its not that hard- use a calculator, but all u have to do is count from 10, to adding 9 more

o-na [289]3 years ago
3 0

Answer:

I'm sorry I don't have a functioning brain anymore-

<em>but I think it's 21.</em>

<em />

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What is 12% of 3500?
kakasveta [241]

Answer:

29,166.6667

Step-by-step explanation:Divide 12% which will turn into 0.12 then divide that with 3500.

6 0
3 years ago
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Which set of sides will make a triangle?
Klio2033 [76]

Answer:

10cm 5cm and 9cm

Step-by-step explanation:

just try this

take any two measurements and add them together if they are larger than the 3rd measurement it will work and all you have to do is do that to each measurement

10+5 is greater than 9

9+5 is greater than 10

9+10 is greater than 5

6 0
3 years ago
Determine the volume of the parallelepiped with one vertex at the origin and the three vertices adjacent to it at (2, â1, â1), (
valentinak56 [21]

Answer:

23

Step-by-step explanation:

Here is the complete question

Find the volume of the parallelepiped with one vertex at the origin and adjacent vertices at (1, 0, -3), (1, 2, 4), and (5, 1, 0).

Solution

We find the volume of the parallelepiped by making a 3 × 3 column matrix whose columns are the corresponding coordinates of the vertices of the parallelepiped.

So, (1, 0, -3), (1, 2, 4)  and (5, 1, 0)

A = \left[\begin{array}{ccc}1&1&5\\0&2&1\\-3&4&0\end{array}\right]

The determinant of A is the volume of the parallelepiped. So,

detA = 1(2 × 0 - 4 × 1) - 1(0 × 0 - (-3) × 1) + 5(0 × 4 - (-3) × 2)

= 1(0 - 4) - 1(0 + 3) + 5(0 + 6)

= 1(-4) - 1(3) + 5(6)

= -4 - 3 + 30

= 23

So the volume of the parallelepiped is 23

4 0
2 years ago
15. What is the width of each bin? (1 point)
Pavel [41]
15) Answer is B because you can clearly see it's only 1 inch
5 0
3 years ago
The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p
VLD [36.1K]

Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

\chi^2_{1-\frac{\alpha}{2}}= 51.770

Chi square critical value for upper tail =

\chi^2_{\frac{\alpha}{2}}= 81.085

80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0
3 years ago
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