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Aleksandr [31]
3 years ago
9

I cant figure out the awnser9+10​

Mathematics
2 answers:
ExtremeBDS [4]3 years ago
5 0

Answer:

19

Step-by-step explanation:

its not that hard- use a calculator, but all u have to do is count from 10, to adding 9 more

o-na [289]3 years ago
3 0

Answer:

I'm sorry I don't have a functioning brain anymore-

<em>but I think it's 21.</em>

<em />

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Step-by-step explanation:

a. The diameter of the circle will be 30 cm

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b. Required percentage = (94.2) * 100 / (4*30)

= 78.5%.

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4 years ago
Show that the set of functions from the positive integers to the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} is uncountable. [Hint: First
Sedbober [7]

Answer:

since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its off functions

Step-by-step explanation:

set = {0,1,2,3,4,5,6,7,8,9}

setting up a one-to-one correspondence between the set of real numbers between 0 and 1

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since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its offfunctions

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3 years ago
A principle of $3100 is invested at 6.5% interest, compounded annually. How much will the investment be worth after 12 years?
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\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3100\\ r=rate\to 6.5\%\to \frac{6.5}{100}\dotfill &0.065\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &12 \end{cases} \\\\\\ A=3100\left(1+\frac{0.065}{1}\right)^{1\cdot 12}\implies A=3100(1.065)^{12}\implies A\approx 6600.198

3 0
3 years ago
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Answer:

4

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