Help with English pls pls pls

Nicole has $9 to spend on cards.She finds friends with the same amount of money to split the cost of a set. One set cost $27. Ea

Dafna1 [17]

Let x be the number of cards in the $27 set, then Nicole has 2 friends that have $9 each. This makes 3 people, therefore each person gets x/3 cards. So each friend would get 1/3 of the cards.

4 0

4 years ago

Read 2 more answers

2. The Walton College of Business was ranked 24th out of all public business schools in the United States in 2005. The dean attr

Sholpan [36]

Answer:

See steps below

Step-by-step explanation:

a)

The null hypothesis is what is already established by previous researches

$\bf H_0:$ Business students average 6.8 hours/week studying.

the alternative hypothesis tries to see how accurate is this based on new evidence. Since the sample averaged 7.2 hours studying, this gives us a base to contrast the hypothesis.

$\bf H_a:$ Business students now average more than 6.8 hours/week studying.

As we can see, this is a right-tailed test.

b)

For a 0.05 significance level, the critical value is the value $\bf Z^*$ such that the area under the Normal curve N(0;1) to the right of $\bf Z^*$ is less than 0.05. This is a very well-known value that can be found by looking up a table or with the computer.

$\bf Z^*$ =1.64

If our z-statistic is greater or equal to 1.64 we have reasons to reject the null and accept the new average.

i.

Our z-statistic is given by the formula

$\bf z=\frac{\bar x - \mu}{\sigma/\sqrt{n}}$

where

$\bf \bar x$ is the mean of the sample

$\bf \mu$ is the mean of the null hypothesis

$\bf \sigma$ is the standard deviation

n is the sample size

Our z-statistic is then

$\bf z=\frac{7.2 - 6.8}{2.2/\sqrt{100}}=1.818181$

ii.

As we already said, our critical value is 1.64

iii.

Since our z-statistic is greater than the critical value, we reject the null hypothesis and accept 7.2 hours/week as the new average.

c)

The p-value for our statistic is the area under the Normal N(0;1) to the right of our z-statistic. (see picture attached).

This area can be calculated either with tables or computer-assisted and is 0.0345.

Comparing our p-value 0.0345 against the level of significance we see that

p-value < level of significance

Conclusion: when the p-value is less than the level of significance we can reject the null.

Remark:

Rejecting the null does not mean that the null is false or the alternative is true. It only means that the probability we had made a mistake by a random sampling error or other reason is less or equal than the p-value.

5 0

4 years ago

Ebra - A 2020-2021

grigory [225]

Answer:

Yuna ran three times as many kilometers.

Evaluate when k = 12.2.

First, write the expression as

✔ 3k

.

Second,

✔ substitute

12.2 in for the variable, k.

Third,

✔ simplify

by

✔ multiplying

3 and 12.2.

The answer is

✔ 36.6

6 0

3 years ago

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Assume federal exemption is, $3300.00, you earn. 37,500.00, the tax rate is 2 3/4%, calculate the tax.

Sauron [17]

3300 exemption

37,500−3,300=34,200 taxable
Tax rate is
2+3/4=2.75% we don't multiply 2by 3/4
Now calculate the amount of tax
34,200×2.75%=940.5

3 0

3 years ago

In June 1990, a small academic press published an initial run of 2,500 copies of linguist Chloe Vermeulen’s first book, Speech a

GREYUIT [131]

Answer:

A) 1525

B) 4636

C) 8479

Step-by-step explanation:

Lest say that The book had been sold x copies in the period of June 1990-June 1995. And we know that the book had been sold 152*x/100 copies in the period of June 1995–June 2000. By June 2000 in total 3843 book had been sold. Therefore number of the copies that sold in the period of June 1990-June 1995 is:

$252*x/100=3843\\x=1525$

number of the copies that sold in the period of June 1995-June 2000 is:

$152*x/100=2318$

For the period June 2000–June 2005 2318*2=4636 book had been sold.

5 0

3 years ago