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Aliun [14]
3 years ago
8

Whats the answer can someone answer please​

Mathematics
1 answer:
Rufina [12.5K]3 years ago
6 0

Answer:

b and c

Step-by-step explanation:

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Find the product: 9|-5|
lions [1.4K]

Answer:

45

Step-by-step explanation:

The absolute value of negative 5 is 5 because it is five units away from zero, and then 9x5=45.

3 0
3 years ago
GCF And LCM of 24, 36, 45
faltersainse [42]

Answer:

Step-by-step explanation:

First lets prime factorize each number

24 = 2 x 2 x 2 x 3

36 = 2 x 2 x 3 x 3

45 = 3 x 3 x 5

GCF = 3    (3 is the only common prime number factor in the 3 numbers)

LCM = 2 x 2 x 2 x 3 x 3 x 5

        = 24 x 3 x 5

        = 72 x 5

        = 360

Happy to help :)

4 0
3 years ago
There are 6060 tables in a restaurant, with 25%25% of them seating 22 people. The tables remaining seat 44 people. How many seat
mestny [16]
60 tables total. 25% of those seat 22 people. 60 X 25% = 15. So 15 of the tables seat 22 people. 
The remaining tables (60 tables - 15 tables = 45 tables) seat 44 people. 

So you have:
(15 tables X 22 seats) + (45 tables X 44 seats) = total seats. 
2310 TOTAL seats. 

6 0
3 years ago
Show your work:<br><br>36+4kt/36-4kt<br><br><br>k=2<br><br>t=3
Elina [12.6K]

Step-by-step explanation: If I replace the variables with the numbers, the equation would be: 36+(4x2x3)/36-(4x2x3). First, solve the numbers in the parentheses. Both numbers in the parenthesis equals 24 because 4x2 is 8 and 8x3 is 24. Then, 36+24/36-24. PEMDAS, so 24/36 is 0.666666666667.  Then 36+0.666666666667 is 36.666666666667. Next, 36.666666666667 minus 24 is 12.666666666667.

5 0
3 years ago
Read 2 more answers
As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.10.
Firdavs [7]

Answer:

New can holds 112.25\,\,cm^3 more than the old can

Step-by-step explanation:

Given: Diameter of the can is 6 cm and height is 12 cm such that volume of can is 339.12\,\,cm^3

Dimensions of the can are increased by a multiple of 1.10

To find: Difference between the volume of new can and volume of old can

Solution:

Volume of can (v) = 339.12\,\,cm^3

Let r, h denote radius and height of the can.

Let R, H denotes radius and height of the new can.

r = diameter/2 = \frac{6}{2}=3\,\,cm

h = 12 cm

R = 3(1.1)=3.3.\,\,cm

H = 12(1.1)=13.2\,\,cm

New volume (V) = \pi (R)^2H=\pi(3.3)^2(13.2)=451.37\,\,cm^3

So,

V-v=451.37-339.12=112.25\,\,cm^3

7 0
4 years ago
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