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3 years ago

Is cell replication the same thing as DNA replication? Or are they two separate things

Mathematics

1 answer:

nikitadnepr [17]3 years ago

8 0

Answer:

Conservative. Replication produces one helix made entirely of old DNA and one helix made entirely of new DNA.

Semi-conservative. Replication produces two helices that contain one old and one new DNA strand.

Dispersive.

Step-by-step explanation:

Replication is the process by which a double-stranded DNA molecule is copied to produce two identical DNA molecules. DNA replication is one of the most basic processes that occurs within a cell.

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$65 a month plus $45

Scilla [17]

Answer: $115 a month

Step-by-step explanation:

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3 years ago

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3<br> What is the difference of<br> 21<br> ?<br> 4

PilotLPTM [1.2K]

Answer:

The difference is 4–3. If you want the difference between 3 and -4, then the difference is 7.

Step-by-step explanation:

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3 years ago

Please help me with this problem:)

krok68 [10]

Answer:

(2,1)

Step-by-step explanation:

3x+y = 7

-2x +y = -3

Solve the second equation for y by adding 2x to each side

-2x+2x +y = -3+2x

y = -3 +2x

Substitute into the first equation

3x+ (-3+2x) = 7

Combine like terms

5x -3 = 7

Add 3 to each side

5x-3+3 = 7+3

5x = 10

Divide by 5

5x/5 = 10/5

x=2

Now we need to solve for y

y = -3 +2x

y = -3 +2(2)

y = -3+4

y =1

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4 years ago

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Can you help me on question seven?!

Shtirlitz [24]

Answer:

Step-by-step explanation:

use PEMDAS

multiplication first

120-20×5+1 =

120-100+1=

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3 years ago

A certain component is critical to the operation of an electrical system and must be replaced immediately upon failure. If the m

nekit [7.7K]

Answer:

Step-by-step explanation:

From the given information:

Assuming we have an integer c to represent the components in the stocks.

Thus, the needed probability can be expressed as:

$P(X_1+X_2+ ........ X_c \ge 2000)$

To break this down, we have:

$P(\sum X_i \ge 2000) = P \Bigg(\dfrac{\sum X_i - 100n}{\sqrt{n \ Var (X)}} \ge \dfrac{2000-100 n }{\sqrt{n \times 900}} \Bigg )$

$P \Bigg(\dfrac{\sum X_i - 100n}{\sqrt{n \ Var (X)}} \ge \dfrac{2000-100 n }{\sqrt{n \times 900}} \Bigg )= P (Z \ge 0.95 ) \ \ \ because \ Z_{0.05} = -1.65 \\ \\ \\ \dfrac{2000-100 n }{\sqrt{n \times 900}} = -1.65 \\ \\ \\ \dfrac{100\ n-2000 }{\sqrt{900n}} = 1.65 \\ \\ 100 n -1.65 \sqrt{900 n }-2000 = 0$

By solving the equation:

n = 23

Thus, relating to the needed condition; n ≥ 23

The needed number of the components that should be in stock should be at least 23.

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3 years ago