From general equation of a line;
y=mx+c
m=
m=
m=-1
y=-x+c
Finding value of c;
using point (-2,0)
0=-(-2)+c
c=-2
y=-x-2
y=mx+c
m=
m=
m=-1
y=-x+c
Finding value of c;
using point (-2,0)
0=-(-2)+c
c=-2
y=-x-2
Please help Fr pleased I’m begging you
1 answer:
Answer:
y = x - 2
Step-by-step explanation:
<u>The answer to this problem is a simple plug-in of the given values into the slope-intercept formula.</u>
Slope intercept formula: y = mx + b
(m = slope)
(b = y intercept)
If the equation has a slope of m = , then the slope-intercept form would be:
y = x
If the y-intercept of an equation is (0 , -2), then the slope intercept form would be:
y = mx - 2
<u>Putting both of these values into an equation would give option A:</u>
y = x - 2
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