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3 years ago

Please help Fr pleased I’m begging you

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

6 0

Answer:

y = $\frac{3}{8}$ x - 2

Step-by-step explanation:

The answer to this problem is a simple plug-in of the given values into the slope-intercept formula.

Slope intercept formula: y = mx + b

(m = slope)

(b = y intercept)

If the equation has a slope of m = $\frac{3}{8}$ , then the slope-intercept form would be:

y = $\frac{3}{8}$ x

If the y-intercept of an equation is (0 , -2), then the slope intercept form would be:

y = mx - 2

Putting both of these values into an equation would give option A:

y = $\frac{3}{8}$ x - 2

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PLZZ HELP!!! NEED ANSWER QUICKLY!!!!

RSB [31]

Answer:

The value of g(x) at x = -3 is 18.

Step-by-step explanation:

Here, the given function is:

g(x) = - 5 x + 3

Now, for the value of x = -3 ,

g (-3) : Substitute the value of x = -3 in g(x) , we get

g (-3) = -5 (-3) + 3

= 15 + 3 = 18

or, g ( -3) = 18

Hence, the value of g(x) at x = -3 is 18.

8 0

4 years ago

Write an equation for a circle with center at (10, –8) and diameter = 12.

ki77a [65]

Answer:

Equation of circle:

(x-10)² + (y+8)² = 36

Step-by-step explanation:

Given that,

Center of the circle is (10, -8)

and diameter = 12

We know that radius is half of the diameter.

So, radius (r) = $\frac{12}{2}$ = 6

Now we have standard form of circle :

(x - h)² + (y - k)² = r²

Where (h,k) is the center of circle and r is the radius.

Now put the value of h, k and r in circle's equation

h =10

k = -8

r = 6

Equation of circle:

(x-10)² + (y+8)² = 36

That's the final answer.

I hope it will help you.

4 0

4 years ago

Solve the system of equations below by graphing both equations with a pencil and paper. What is the solution? y = x+1 1 X+ 3 2.

Troyanec [42]

Answer:

D. (4, 5)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Algebra I

Solving systems of equations using substitution/elimination
Solving systems of equations by graphing

Step-by-step explanation:

Step 1: Define systems

y = x + 1

y = 1/2x + 3

Step 2: Solve for x

Substitute in y: x + 1 = 1/2x + 3
Subtract 1/2x on both sides: 1/2x + 1 = 3
Subtract 1 on both sides: 1/2x = 2
Divide both sides by 1/2: x = 4

Step 3: Solve for y

Define original equation: y = x + 1
Substitute in x: y = 4 + 1
Add: y = 5

Step 4: Graph

We can confirm our answer.

8 0

3 years ago

What is the common denominator of (5/x^2-4) - (2/x+2) in the complex fraction (2/x-2) - (3/x^2-4)/(5/x^2-4) - (2/x+2)

PIT_PIT [208]

9514 1404 393

Answer:

common denominator: (x² -4)
simplified complex fraction: (2x +1)/(9 -2x)

Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

a² -b² = (a -b)(a +b)

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

$\dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}$

3 0

3 years ago

Is 21/2:3 and 16:6 equivalent

Minchanka [31]

Answer
21/2:3 and 16:6 are not equivalent

6 0

2 years ago