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2 years ago

Calcular en cuanto se convertira, un capital de $15,500 en 8 meses al 6.5%

1 answer:

8 0

En algunos bancos, cuentas de ahorro o incluso en prestamos y empeños podemos observar que se cobra un interés mensual. Esto no significa que todos los intereses deban ser así.

El periodo, es el tiempo en el que se aplica el interés, este puede ser anual, mensual, semanal, o incluso por día.

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Barbara can pay either $80 per month or one lump sum of $800 per year for car insurance. How much does she save yearly if she ch

Schach [20]

Answer:

$160

Step-by-step explanation:

In the monthly payment option she would pay $80 per month, therefore in a year (12 months) she would pay:

$80*12 = $960

We can see that this amount is greater than the $800 she would pay in the lump sum payment option.

The money she would save is:

$960 - $800 = $160

She would save $160 yearly with the lump sum payment option.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B4%7D%20%20-%206%20%7Bx%7D%5E%7B3%7D%20%20%2B%2022%20%7Bx%7D%5E%7B2%7D%20%20-%2

alexira [117]

Answer:

x = 2, 1 + 3i, 1 − 3i

Step-by-step explanation:

Find the Roots (Zeros)

x^4 − 6x^3 + 22x^2 − 48x + 40

Set x^4 − 6x^3 + 22x^2 − 48x + 40 equal to 0. x^4 − 6x^3 + 22x^2 − 48x + 40 = 0

Solve for x.

Factor the left side of the equation.

Factor x^4 − 6x^3 + 22x^2 − 48x + 40 using the rational roots test.

(x − 2) (x^3 − 4x^2 + 14x − 20) = 0

Factor x^3 − 4x^2 + 14x − 20 using the rational roots test.

(x − 2) (x − 2) (x2 − 2x + 10) = 0

Combine like factors.

(x − 2)2 (x^2 − 2x + 10) = 0

If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

(x − 2)^2 = 0

x^2 − 2x + 10 = 0

Set (x − 2)^2 equal to 0 and solve for x.

Set (x − 2)^2 equal to 0.

(x − 2)^2 = 0

Solve (x − 2)^2 = 0 for x.

x = 2

Set x^2 − 2x + 10 equal to 0 and solve for x.

Set x^2 − 2x + 10 equal to 0. x^2 − 2x + 10 = 0

Solve x^2 − 2x + 10 = 0 for x.

Use the quadratic formula to find the solutions.

−b ± (√b^2 − 4 (ac) )/2a

Substitute the values a = 1, b = −2, and c = 10 into the quadratic formula and solve for x.

2 ± (√(−2)^2 − 4 ⋅ (1 ⋅ 10))/2 ⋅ 1

Simplify.

Simplify the numerator.

x = 2 ± 6i/ 2.1

Multiply 2 by 1

x = 2 ± 6i/2⋅1

Simplify

2 ± 6i/2

x = 1 ± 3i

The final answer is the combination of both solutions.

x = 1 + 3i, 1 − 3i

The final solution is all the values that make (x − 2)2 (x2 − 2x + 10) = 0 true.

x = 2, 1 + 3i, 1 − 3i

3 0

3 years ago

Help please I don’t understand

mestny [16]

Answer:

It is xy

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

We know that a class interval must be greater than what the I formula solution is; however... What is the solution for class int

stich3 [128]

Answer:

Therefore the answer is 20.

Step-by-step explanation:

We know that

class interval = range / number of classes

But here number of classes is not given , so we use the formula

class interval = range / ( 1+ 3.322 log N)

where , range =maximum - minimum = 220-100 = 120

N= number of observations = 50

class interval = 120 / ( 1+ 3.322 * log 50) = 18.06

Rounding up to a convinient number

Thus , class intervai = 20

Therefore the answer is 20.

3 0

2 years ago

1.08t can be written as (1.081/12)12t to give the approximate equivalent monthly interest rate based on an annual rate of 8%. Us

kobusy [5.1K]

Because t is given in years and 1.08 = 1 + 0.08, the annual percent increase
is 8%.
To find the monthly percent increase that gives an 8% annual increase,
use the fact that
t = $\frac{1}{12} * 12 t$ 
and the properties of exponents to rewrite the
model in a form that reveals the monthly growth rate.

$1.08^{t} 
= 1.08^{(1/12)(12t)} 
= (1.08^{1/12}) ^{12t} 
= 1.0064634^{12t}$

6 0

3 years ago

Read 2 more answers