Answer:
The answer is "y > x-2 and y < x + 1"
Step-by-step explanation:
In the given question the last choice, that is "y > x-2 and y < x + 1" which can be defined in the following diagram.
So the problem has no symbols, but we're going to multiply because the fraction on the left is right next to the parentheses.
-5/2 * 1/10x = -5x/20
I put "x" next to the 5 because the "x" counts as part of the numerator. Now that it's 5x over 20 that equals one, I'd first reduce -5x/20 into -x/4, then do
-x/4 * -4 = 1 * -4
To make the "x" side equal one, we have to multiply both sides by -4, to make both sides equal.
x = -4.
Answer:
9 nickels
Step-by-step explanation:
He has 17 coins.
$1.25 is 12 dimes and 1 nickel. But that is only 13 coins.
$1.25 can only be 17 coins if there were 9 nickels and 8 dimes.
To cube something means to take it by 3, when used in the sentance, 3 cubed it refers to 3^3 power which means 3*3*3 which equals 21. In this context I'm guessing that they mean 50^3 which would be $125,000.
Hope this helps!=)
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3