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nadezda [96]
2 years ago
10

1.08t can be written as (1.081/12)12t to give the approximate equivalent monthly interest rate based on an annual rate of 8%. Us

e the properties of exponents to transform the expression into a single exponent expression
Mathematics
2 answers:
viktelen [127]2 years ago
8 0

Answer:

(1.006)^12t

Step-by-step explanation:

I just did it on UsaTestPrep.

(1.08^1/12)^12t ≈ (1.006)^12t

Hope this helps!

kobusy [5.1K]2 years ago
6 0
<span>Because <span>t <span>is given in years and 1.08 <span>= <span>1 <span>+ <span>0.08, the annual percent increase
<span>is 8%.
To find the monthly percent increase that gives an 8% annual increase,
<span>use the fact that
t = \frac{1}{12} * 12 t<span><span><span><span>
<span><span><span><span>and the properties of exponents to rewrite the
model in a form that reveals the monthly growth rate.</span></span></span>
</span></span></span></span></span></span></span></span></span></span></span></span></span></span>
1.08^{t} &#10;= 1.08^{(1/12)(12t)} &#10;= (1.08^{1/12}) ^{12t} &#10;=  1.0064634^{12t}
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Alex17521 [72]

Answer:

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Step-by-step explanation:

In the given question the last choice, that is "y > x-2 and y < x + 1" which can be defined in the following diagram.

7 0
3 years ago
How do you do this problem
Ainat [17]
So the problem has no symbols, but we're going to multiply because the fraction on the left is right next to the parentheses. 

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4 0
2 years ago
Joe has 17 coins, nickels and dimes, that total up to $1.25. How many nickels does he have?
kifflom [539]

Answer:

9 nickels

Step-by-step explanation:

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6 0
3 years ago
"Zachary invested $50 and was able to triple his money in two years. Kayla also began with $50 in investments, and was able to c
horsena [70]
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3 0
2 years ago
Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

5 0
3 years ago
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