Answer:
3
Step-by-step explanation:

Hope this helps!
Answer:
Equation of line is y=(12/5)x+2
Step-by-step explanation:
The slope of line AB is -5/12. The line passing X is perpendicular to line AB and hence have a slope of 12/5. The slope intercept form is given by y=mx+c.
Now, point X satisfies the equation. Plugging in the slope of the line we end up with
y=(12/5)*x+c, now to find c
-10=(12/5)*(-5)+c, c=2
Equation of line is y=(12/5)x+2
You don't even need the picture to solve this one.
You said that h = 5 cot(Θ) , and you said that Θ is 30 degrees.
All you need now is to find the cotangent of Θ, plop that into the equation,
and the solution practically jumps off the paper into your lap.
To find the cotangent of 30 degrees, you can use a calculator, look it up
in a book, read it off of a slide rule if you have one, draw a picture of a
30-60-90 right triangle etc. You'll find that the cotangent of 30 degrees
is √3 . That's about 1.732 .
So your equation is h = 5 (1.732) = <em>8.66 </em>(rounded)
Apparently, somebody gave you the equation, and asked you to find 'h'.
Once you had the equation, you didn't even need to know that 'h' has
anything to do with a triangle.
You can use elimination to solve systems of equations with 3 equations. I know how to solve systems of equatons with 3 equations, but I use a different process, I don't know how to use the elimination method.