sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
<u>Step-by-step explanation:</u>
We need to find sum of sequence : 46 + 42 + 38 + ... + (-446) + (-450)
Given sequence is an AP with following parameters as :

So , Let's calculate how many terms are there as :
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⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Sum of an AP is :
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⇒ 
⇒ 
⇒ 
Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
Answer:
39 or 1/39
Step-by-step explanation:
You need to divide these but it depends on how you divide them
The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327
<h3>How to determine the product of the numbers?</h3>
The numbers are given as
853 and 59
By using the standard algorithm i.e. the partial product method, we have the following equation
853 * 59 = 853 * (50 + 9)
Open the bracket
So, we have
853 * 59 = 853 * 50 + 853 * 9
Evaluate the products
So, we have
853 * 59 = 42650 + 7677
The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650
Next, we evaluate the sum
853 * 59 = 50327
This means that the final product is 50327
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If it's compounded annually, it basically means the interest rate will apply once a year.
So the answer will be 1.
Given:
There are given the edge of the cube-shaped aquarium has 3 feet.
Explanation:
To find the value, we need to use the volume of the cube formula:
So,
From the formula of volume:

Where
a represents the value of edge.
So,
Put the value of edge into the above formula:
Then,

Now,
The water has a density of 62 pounds per cube foot.
According to the question:
If the weight of 1 cubic foot of water is 62 pounds, then the weight of 27 cube feet water is:

Final answer:
Hence, the water weight of the full aquarium is 1674 pounds, and the table only susupports00 pounds. So the table cannot hold the aquarium.
And,
No, the density of water would not change.