1a) f(x) = I x+2 I. This is a piece-wise graph ( V form)
x = 0 →f(x) =2 (intercept y-axis)
x = -2→f(x) = 0 (intercept x-axis)
x = -3→f(x) = 1 (don't forget this is in absolute numbers)
x = -4→f(x) = 2 (don't forget this is in absolute numbers)
Now you can graph the V graph
1b) Translation: x to shift (-3) units and y remains the same, then
f(x-3) = I x - 3 + 2 I = I x-1 I
the V graph will shift one unit to the right, keeping the same y. Proof:
f(x) = I x-1 I . Intercept x-axis when I x-1 I = 0, so x= 1
Answer:
c = -6
Step-by-step explanation:
To find the value of c to make the line pass through the point K = (2, -3), we just need to use the values of x = 2 and y = -3 in the equation, then we find the value of c.
So, we have that:
y - 1.5*x = c
(-3) - 1.5 * (2) = c
-3 - 3 = c
c = -6
So the value of c is -6
To check if the value is correct, we can use the value x = 2 and see if the value of y is -3:
y - 1.5*x = -6
y - 1.5*2 = -6
y - 3 = -6
y = -6 + 3 = -3
So it's correct.
Answer:
Q1: 3
Q2: reflected (a)
Q3: a
Q4: false
Q5: 90°(b)
Step-by-step
srry if it's wrong cuz I dont remember some of these but I tried
