<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
just sub in the numbers into the equation to replace the X ..
example for
a) h(7) : 44
Step-by-step explanation:
h(7) : x^2 -5
sub in 7 into the equation to replace X
so you get
(7)^2 - 5
49-5
44
Answer:H2+Br2-->2HBr
Step-by-step explanation:
The amount of atoms on the left side must be equal to the amount of atoms on the right side for each element.
On the left you got 2xH and 2xBr.
This means you must have the same amount on the right.
2HBr =2xH + 2xBr
Answer:
SSS
Step-by-step explanation:
IM CORRECT
Answer: A
Step-by-step explanation:
because i nsaid sooooo
