3√24 + 2√3(√3-2√18) =
3(√(4*6) + 2√3( √3-2√(2*9)) =
3*2√6 + 2√3 ( √3 - (2*3) √2) =
6√6 + 2√3(√3 - 6√2) =
6√6 + 6 - 12√3*√2 =
6√6 + 6 - 12√(6) =
6 - 6√6 = 6(1-√6)
We can use the difference of two squares, which is:
x^2 + y^2 = (x-y)(x+y)
So,
(9m-7)(9m+7)
Hope this helps!
Answer:
2
Step-by-step explanation:
Given the data : 29, 2, 28, 30, 26, 31
Outlier ;
Lower :Q1 - (1.5 * IQR)
Upper : Q3 + (1.5 * IQR)
Q1 = Lower quartile ; Q3 = upper quartile ; IQR = Interquartile range
Using calculator :
Q1 = 26
Q3 = 30
IQR = (Q3 - Q1) = 30 - 26 = 4
Lower : 26 - (1.5 * 4) = 20
Upper : 30 + (1.5 * 4) = 36
Hence, the number in the given data which falls outside the range is 2
Answer:
225
Step-by-step explanation:
i used a calculater and did 90 divided by .40
Step-by-step explanation:
1. Add all the different candies together
1/8 + 1/2 + 2/3=
2. Find the lowest common multiple of all the denominators
All the denominators can evenly multiply to 24 so 24 is the Lowest Common Denominator.
3. Multiply to make all the denominators 24
8x3=24 2x12=24 3x8=24
4. Whatever you did to the denominators, do the same thing to the numerators of that specific denominator.
1x3/8x3 1x12/2x12 2x8/3x8
5. Now that the denominators are the same for all the fractions, add all the numerators together.
3/24 + 12/24 + 16/24
3+12+16= 31
ANSWER: Natalie had 31/24 pounds of candy in all
Note: The decimal form is 1.292 pounds
