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ser-zykov [4K]
3 years ago
14

If y=1/2x+4, then find the equation of the line parallel through the point (6,3).

Mathematics
1 answer:
tatyana61 [14]3 years ago
5 0

Answer:

x=2y

Step-by-step explanation:

random guess

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In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were o
ad-work [718]

The question is incomplete. Here is the complete qeustion.

In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were obtained: 0.10 0.13 0.16 0.15 0.14 0.008 0.15

(a) Construct a 99% confidence interval for the mean nitrogen-oxide emissions of all cars.

(b) If the EPA requires that nitrogen-oxide emissions be less than 0.165 g/mi, based on the 99% confidence interval in (a), can we safely conclude that this requirement is being met?

Answer: (a) 0.089 ≤ μ ≤ 0.171

(b) No

Step-by-step explanation:

(a) To determine the confidence interval, first calculate the mean (X) and standard deviation (s) of the sample

X = \frac{0.1+0.13+0.16+0.15+0.14+0.08+0.15}{7}

X = 0.13

s = \sqrt{\frac{(0.1-0.13)^{2} + (0.13 - 0.13)^{2} + ... + (0.15 - 0.13)^{2}}{7-1} }

s = 0.029

The degrees of freedom is

N - 1 = 7 - 1 = 6

And since the confidence is of 99%:

α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005

The t-test statistics for t_{6,0.005} is 3.707

(Value found in the t-distribution table)

Now, calculate Error:

E = t_{6,0.005} . \frac{s}{\sqrt{N} }

E = 3.707. \frac{0.029}{\sqrt{7} }

E = 0.041

The interval will be:  

0.13 - 0.041 ≤ μ ≤ 0.13+0.041

0.089 ≤ μ ≤ 0.171

(b) No, because according to the interval, the nitrode-oxide emissions range from 0.089 to 0.171, which is greater than required by EPA.

7 0
3 years ago
A spherical hot-air balloon has a diameter of 55 feet. When the balloon is inflated, the radius increases at a rate of 1.5 feet
abruzzese [7]

Answer:

The time it would take to inflate the balloon to approximately two-thirds of its maximum volume is approximately 46.90 minutes

Step-by-step explanation:

The given parameters are;

The diameter of  the balloon  = 55 feet

The rate of increase of the radius of the balloon when inflated = 1.5 feet per minute

We have;

dr/dt = 1.5 feet per minute = 1.5 ft/min

V = 4/3·π·r³

The maximum volume of the balloon = 4/3 × 3.14 × 55³ = 696556.67 ft³

When the volume is two-thirds the maximum volume, we have;

2/3 × 696556.67 ft³ = 464371.11 ft³

The value of the radius, r₂ at that point is found as follows;

4/3·π·r₂³ = 464371.11 ft³

r₂³ = 464371.11 ft³ × 3/4 = 348278.33 ft³

348278.333333

r₂ = ∛(348278.33 ft³) ≈ 70.36 ft

The time for the radius to increase to the above length = Length/(Rate of increase of length of the radius)

The time for the radius to increase to the above length ≈ 70.369 ft/(1.5 ft/min) ≈ 46.90 minutes

The time it would take to inflate the balloon to approximately two-thirds of its maximum volume ≈ 46.90 minutes.

4 0
3 years ago
Which value would not be part of the domain of the inverse of the given relation?
Sidana [21]
Not sure sorry I tried
3 0
3 years ago
Help asap will give brainliest
ArbitrLikvidat [17]

<u>Answer:</u>

• Equation = 2(\frac{7}{4}w  + w) = 176

• length = 56 ft

• width = 32 ft

<u>Step-by-step explanation:</u>

The ratio of the length to width is 7:4.

∴ \frac{l}{w} = \frac{7}{4}

⇒ l = \frac{7}{4} w                 [Equation 1]

We know that the perimeter of the garden is 176 feet.

∴ 2(l + w) = 176

⇒ 2(\frac{7}{4}w  + w) = 176

⇒ \frac{7}{4} w + w = 88        [From Equation 1]

⇒ \frac{7 w + 4w}{4}  = 88

⇒ \frac{11w}{4} = 88

⇒ 11w = 352

⇒ w = \bf 32 \space\ ft

We know from Equation 1 that:

l = \frac{7}{4} w

∴ l = \frac{7}{4} (32)

⇒ l = \bf 56 \space\ ft

7 0
2 years ago
Write 1.04 x 10^2 in standard form
Natasha2012 [34]
<span> 1.04 x 10^2 in standard form = 104

----------------</span>
7 0
3 years ago
Read 2 more answers
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