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Alenkinab [10]
3 years ago
9

5 = 5(y - 2)A. -3B. 3C. -1D. 1​

Mathematics
2 answers:
Bess [88]3 years ago
8 0

Answer:

Its 3

Step-by-step explanation:

STALIN [3.7K]3 years ago
5 0
The answer to this question 3
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2x+4

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Ann made 75 cookies to give equally to her friends. She put 4 cookies in each bag. She gave all of her left over cookies to her
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Answer: how  many friends did she have ?

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3 years ago
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Determine the value of logb b. Explain your reasoning.
balandron [24]

Answer:

Suppose that logb b = x.

bx = b (Use the definition of a logarithm.)

bx = b1

x = 1 (Use the common base property.)

So, logb b = 1.

4 0
3 years ago
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Could anyone tell me if I’m right. This is a gradient of a line question
pshichka [43]

Answer:

See Below (it is correct)

Step-by-step explanation:

First point given ----  A(-3,0)

2nd point given ----- B(4,0)

The slope is the "change in quantity y" divided by "change in quantity x"

The change would be from 2nd point to 1st point. So,

Change in quantity y is 0 - 0 = 0

Change in quantity x is 4 - (-3) = 4 + 3 = 7

So, slope would be:

Slope = 0/7 = 0

The slope is 0 (which means it is a horizontal line)

3 0
3 years ago
Fewer young people are driving. In year A, 67.9% of people under 20 years old who were eligible had a driver's license. Twenty y
aleksley [76]

Answer:

                                 Case a                               Case b

margin of error       0.0216                                   0.0231

Interval estimate   (0.7016 , 0.6795)                (0.5031 , 0.4569)

margin of error is not same in both cases.

Step-by-step explanation:

a

At 95% confidence interval the interval estimate of number of 20 year old drivers in year A can be computed as

  p'  ±  z  \sqrt{\frac{p'(1-p')}{n} }

= 0.68 ± 1.96 \sqrt{\frac{0.68(1-0.68)}{1800} }

= 0.7016 , 0.6795

the margin of error can be written as

z  \sqrt{\frac{p'(1-p')}{n} }

= 1.96 \sqrt{\frac{0.68(1-0.68)}{1800} }

= 0.0216

b

At 95% confidence interval the interval estimate of number of 20 year old drivers in year B can be computed as

p'  ±  z  \sqrt{\frac{p'(1-p')}{n} }

= 0.48 ± 1.96 \sqrt{\frac{0.48(1-0.48)}{1800} }

=  0.5031 , 0.4569

the margin of error can be written as

z  \sqrt{\frac{p'(1-p')}{n} }

=  1.96 \sqrt{\frac{0.48(1-0.48)}{1800} }

= 0.0231

c

Sample size is same in case A and B but proportion is different in both cases so margin of error is different in both cases

3 0
3 years ago
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