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VladimirAG [237]
3 years ago
13

Urgent need ASAP

Computers and Technology
1 answer:
Andreyy893 years ago
4 0

Answer:

{3 quarters, 1 dime, 2 nickels, 5 pennies}  or  

 {3 quarters, 2 dimes, 1 nickel, 5 pennies}

Explanation:

You need change for a nickel, so 5 pennies.

You need change for a dime, so 1 more nickel.

You need change for a quarter, so a dime and a nickel, or two dimes more.

You need change for $1, so 3 more quarters.

You need a minimum of 11 coins. You can use 2 nickels and a dime, or 2 dimes and a nickel to get the values between 15¢ and 25¢. The latter gives you the ability to continue up to $1.05.

 pls mark brainliest

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The Imitation Game

5 0
3 years ago
My dog peed in the house last week
Solnce55 [7]

Answer:

my dog chewed up the couch

Explanation:

5 0
4 years ago
Read 2 more answers
Minerals can form deep inside Earth’s crust by
ipn [44]

ANSWER:

Minerals can form deep inside earth's crust by the crystallization of melted materials. There are two ways on how minerals are formed: crystallization of melted materials and the crystallization of materials dissolved in water.

Hope this helps!

5 0
3 years ago
A variable like userNum can store a value like an integer. Extend the given program to print userNum values as indicated.(1) Out
dimulka [17.4K]

Answer:

The program in Java is as follows:

import java.util.*;

public class Main{

public static void main(String[] args) {

 int userNum;

 Scanner input = new Scanner(System.in);

 System.out.print("Enter integer: ");

 userNum = input.nextInt();

 System.out.println("You entered "+userNum);

 System.out.println(userNum+" squared is "+(userNum*userNum));

 System.out.println(userNum+" cubed is "+(userNum*userNum*userNum));

 int userNum2;

 System.out.print("Enter another integer: ");

 userNum2 = input.nextInt();

 int sum= userNum + userNum2; int product = userNum2 * userNum;

 System.out.println(userNum+" + "+userNum2+" = "+sum);

 System.out.println(userNum+" * "+userNum2+" = "+product); } }

Explanation:

This declares userNum

 int userNum;

 Scanner input = new Scanner(System.in);

This prompts the user for input

 System.out.print("Enter integer: ");

This gets user input from the user

 userNum = input.nextInt();

Number (1) is implemented here

 System.out.println("You entered "+userNum);

Number (2) is implemented here

 System.out.println(userNum+" squared is "+(userNum*userNum));

 System.out.println(userNum+" cubed is "+(userNum*userNum*userNum));

This declares another variable userNum2

 int userNum2;

This prompts the user for another input

 System.out.print("Enter another integer: ");

This gets user input from the user

 userNum2 = input.nextInt();

This calculates the sum and the product

 int sum= userNum + userNum2; int product = userNum2 * userNum;

Number (3) is implemented here

 System.out.println(userNum+" + "+userNum2+" = "+sum);

 System.out.println(userNum+" * "+userNum2+" = "+product);

8 0
3 years ago
Statement: There are two files. One file, "badIP_list.txt" has a listing of known bad IP addresses. These addresses were extract
lapo4ka [179]

Answer:

See explaination

Explanation:

SOURCE CODE IN PYTHON:

inp=open('badIP_list.txt', 'r') #opening file for input

badIPs=[i.rstrip('\n') for i in inp.readlines()] #reading bad IPs

inp.close() #closing file

inp=open('server_logs.txt', 'r') #opening file for input

IPs=[i.rstrip('\n') for i in inp.readlines()] #reading all IPs from log

inp.close() #closing file

uniqueBadIPs=[] #to store unique bad IPs

countBadIPs=0 #to store count of bad IPs

countIPs=0 #to store count of all IPs

for IP in IPs: #iterating through the log of IPs

if IP in badIPs: #checking if IP is bad

countBadIPs+=1

if IP not in uniqueBadIPs: #checking if bad IP is unique

uniqueBadIPs.append(IP)

countIPs+=1

out=open('filter_list.txt', 'w') #opening file for output

out.write('_________________________________________________________\n')

out.write('Date : 26/07/2018\nName : Last, First\nMajor: CS\n\n')

out.write('Server logs contained these known bad IP addresses:\n')

for IP in uniqueBadIPs: #output the unique bad IPs

out.write(IP+'\n')

out.write('\n')

out.write('Total unique known bad IP\'s detected:\n'+str(len(uniqueBadIPs))+'\n\n')

out.write('Percentage of bad IP addresses in server logs:\n{:.2f}%\n'.format(countBadIPs*100/countIPs))

out.write('_________________________________________________________')

out.close() #closing file

5 0
4 years ago
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