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2 years ago

X. y

Mathematics

2 answers:

vladimir1956 [14]2 years ago

6 0

The slope is 2 because slope formula

bija089 [108]2 years ago

5 0

Answer:

slope is 2

Step-by-step explanation:

Let the equation be y = mx +c , which is general form of equation for straight line or linear equation.

where m is slope , c is y intercept and ( x , y ) are ordered pair.

putting all the given values,

( refer attachment )

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lesantik [10]

First and the fourth

8 0

2 years ago

A large bag contains 12/15 pound of granola.How many 1/3 pound bags can be filled with this amount of granola? How much granola

ipn [44]

First you want to turn 1/3 into 5/15.
You can multiply 5/15 x 2 = 10/15. Thats as far as you get.
12/15
-10/15
__________
2/15 Pounds of granola left.

4 0

2 years ago

Writing two column proofs. Given: BC bisects ABM M ABD=52° prove: m B =26°

rjkz [21]

Answer:

Look at attachment!

Step-by-step explanation:

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7 0

2 years ago

If lim x-> infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b

MAXImum [283]

We have

$\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}$

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0$

The rational term vanishes as x gets arbitrarily large, so we can ignore that term, leaving us with

$\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0$

and this happens if a = 1 and b = -1.

To confirm, we have

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-x+1\right)=\lim_{x\to\infty}\frac{x^2-(x-1)(x+1)}{x+1}=\lim_{x\to\infty}\frac1{x+1}=0$

as required.

3 0

2 years ago

Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following p

aev [14]

Answer:

P(X < 3) = 0.7443

Step-by-step explanation:

We are given that the random variable X has a binomial distribution with the given probability of obtaining a success. Also, given n = 6, p = 0.3.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 6

r = number of success = less than 3

p = probability of success which in our question is 0.3.

LET X = a random variable

So, it means X ~ $Binom(n=6, p=0.3)$

Now, Probability that X is less than 3 = P(X < 3)

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

= $\binom{6}{0}0.3^{0} (1-0.3)^{6-0}+ \binom{6}{1}0.3^{1} (1-0.3)^{6-1}+ \binom{6}{2}0.3^{2} (1-0.3)^{6-2}$

= $1 \times 1 \times 0.7^{6} +6 \times 0.3^{1} \times 0.7^{5} +15 \times 0.3^{2} \times 0.7^{4}$

= 0.11765 + 0.30253 + 0.32414 = 0.7443

Therefore, P(X < 3) = 0.7443.

5 0

3 years ago