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natulia [17]
3 years ago
6

2. The senior class is having a fundraiser to help pay for the senior trip. Selling a box of chocolates yields a profit of $2.45

, while selling a box of cookies yields a profit of $2.70. The demand for cookies is at least twice that of chocolates, but the amount of cookies produced must be no more than 550 boxes plus 3 times the number of chocolates produced. Assuming that the senior class can sell every box that they order, how many boxes of each should they order to maximize profit if they cannot order more than 1950 boxes combined?
Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

Step-by-step explanation:

350 chocolate     1599 of cookies

Step-by-step explanation:

c= box of chocolates

k=box of coockies

k< 550+3c , so   k-3c<550              

 k+c< 1950

 k-3c<550

I will multiply  the second by 3

k -  3c <  550

3k +3c <  5850

ADD BOTH

4k  <  6400

k  <   1600    Cookies should be less than 1600

Since cookies yield more than chocolates , to maximize profit they need to sell the maximum amount of cookies they can

1599 +350= 1949  (less than 1950)

The amount of cookies produced must be no more than 550 boxes plus 3 times the number of chocolates produced.

1599< 3(350) +550= 1050+550=1600)

1599<1600

1599 is at least double of 350 (it could be more than double)

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the last one

Step-by-step explanation:

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DJ Titus is making a playlist for a radio show; he is trying to decide what 10 songs to play and in what order they should be pl
Dominik [7]

Answer:

Different playlists possible = 18287141644800

Step-by-step explanation:

Given - DJ Titus is making a playlist for a radio show; he is trying to

            decide what 10 songs to play and in what order they should be

            played.

            Step 1 of 2 : If he has his choices narrowed down to 7 blues,

                                 7 disco, 5 pop, and 7 reggae songs.

To find - He wants to play no more than 4 reggae songs.

              How many different playlists are possible ?

Proof -

Given that he wants to play no more that 4 reggae songs.

So the possibility of choice of reggae song is 0, 1, 2, 3, 4

Now,

Case I -

If 0 reggae song is selected

⇒All 10 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₁₀ ₓ ⁷C₀ = 92,378

Case II -

If 1 reggae song is selected

⇒All 9 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₉ ₓ ⁷C₁ = 646,646

Case III -

If 2 reggae song is selected

⇒All 8 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₈ ₓ ⁷C₂ = 1,587,222

Case IV -

If 3 reggae song is selected

⇒All 7 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₇ ₓ ⁷C₃ = 1,763,580

Case V -

If 4 reggae song is selected

⇒All 6 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₆ ₓ ⁷C₄ = 949,620

So,

Total possible ways = 92,378+ 646,646+ 1,587,222+ 1,763,580+ 949,620

                               = 5,039,446

⇒Total possible ways = 5,039,446

Now,

Also the 10 songs selected can arranged themselves in 10! ways. ( because order of song played does not matter )

∴ we get

Different playlists possible = 10! × 5,039,446

                                          = 18287141644800

⇒Different playlists possible = 18287141644800

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Step-by-step explanation:

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