Answer:
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You will need 252 mL of pure water to obtain 0.25 mL of the desired 25% solution.
If we add X amount of water to the solution, the total amount of solution is 375+X.
And that must be 25%.
<h3>
What is the amount of solute in the current solution?</h3>
The amount of solute in the current amount of solution is
0.6(375)=225.
That amount won't change by adding water.
So we set up the equation so that the amount of solute divided by the new total amount of solution equals 25%.
225/(375+X)=0.25
cross multiply and solve
225/0.25=(375+X)
900-375=X
X=525
The pure water will you need to add to obtain the desired solution is 525.
Then we check 225/(375+525)=0.25.
To learn more about the mixture problem visit:
brainly.com/question/24647756
#SPJ1
First you need to expand them
(x^2 + 9) + (2x + 6)
then you add them together
x^2 + 2x + 15
now you can factorise it
i hope this helped you
