Answer:
Hi, for this exercise we have two laws to bear in mind:
Morgan's laws
NOT(А).NOT(В) = NOT(A) + NOT (B)
NOT(A) + NOT (B) = NOT(А).NOT(В)
And the table of the Nand
INPUT OUTPUT
A B A NAND B
0 0 1
0 1 1
1 0 1
1 1 0
Let's start!
a.
Input OUTPUT
A A A NAND A
1 1 0
0 0 1
b.
Input OUTPUT
A B (A NAND B ) NAND (A NAND B )
0 0 0
0 1 0
1 0 0
1 1 1
C.
Input OUTPUT
A B (A NAND A ) NAND (B NAND B )
0 0 0
0 1 1
1 0 1
1 1 1
Explanation:
In the first one, we only need one input in this case A and comparing with the truth table we have the not gate
In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.
In the third case we have that the OR is A + B and we know in base of the morgan's law that:
A + B = NOT(NOT(А).NOT(В))
So, we have to negate the two inputs and after make nand with the two inputs negated.
I hope it's help you.
Answer:
The answer is "Option D".
Explanation:
Web service is also known as an online open software product, which uses a common XML messaging service system. It is used service like HTTP, SOAP, etc, that encrypts messages from all web services.
- It uses the internet, that enables you the interface or application for the user interaction or exchanging data.
- It will turn the software into web apps.
private static String removeFromString(String old, String frag)
{
int i = old.indexOf(frag);
while (i> -1) {
String rest = old.substring(i + frag.length());
System.out.println("rest = " + rest);
old = old.substring(0, i);
System.out.println("rest = " + old);
old = old + rest;
System.out.println("rest = " + old);
i = old.indexOf(frag);
System.out.println("i = "+ i);
}
return old;
}
Here the index of first occurrence is obtained outside the “while loop” and if this loop runs until index value is >-1. It extracts the rest of the characters other than “frag” from the index and all the characters for which the given set of characters are removed.
Explanation:
The below code has been written in C language
void rotateright(int list[], int n)
{
int x = list[n-1]
int i;
for (i = n-1; i > 0; i--)
list[i] = list[i-1];
list[0] = x;
}
void rotateleft(int list[], int n)
{
int x = list[0]
int i;
for (i = 1; i < n-1 ; i++)
list[i] = list[i+1];
list[n-1] = x;
}
int main()
{
int list[] = {x1, x2, x3, ... x(n-1),xn}
int i;
int n = sizeof(list);
rotateright(list, n);
rotateleft(list, n);
return 0;
}
As there are no options given, I will simply mention the three most liquid accounts in order:
<span>1. Checking Account
2. Savings Account
3. Money Market Deposit Account
Account liquidity refers to the ease and comfort with which you can take your money out of an account from a bank, there are various bank accounts which can be referred to as liquid assets.</span>
