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scoundrel [369]
3 years ago
13

Please help me, tomorrow is the deadline.

Mathematics
1 answer:
Helen [10]3 years ago
4 0

I only know the substitutional method so I am going to give you the answers.

1. (remember I am only using the substitutional method, I am doing the method wrong...)

x + y = 10, 3x - y = 2, 5(3x-y) = 5(2), 15x - 5y = 10, 15x -5y = x + y, 14x = 6y, x = 3/7 y , 3/7 y + y = 10, 10/7y = 10, 10 y = 70, y = 7, 14x = 42. x =3

y = 7, x = 3

2. What I know:

x + y = 6

x + 2x = 6

3x = 6

x = 2, y =4

3. I am using a video to help me remember.

x = 2y + 3     2x + 3y = -3.

-3 = 2y - x     -3 = 3y + 2x

0 = - y + 3x,     y = 3x

x = 2(3x) + 3,   x = 6x + 3

-5x = 3,            x = -3/5

y = 3(-3/5)

y = -9/5, x = -3/5

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Drupady [299]

Answer:

Step-by-step explanation:

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4 years ago
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Alenkinab [10]

Any even number raised to any power will remain even. (e.g. 2² = 4, 2³ = 8, etc)

Any odd number raised to any power will remain odd. (e.g. 1² = 1³ = ... = 1, 3⁴ = 81, etc)

So (n+1)^{2^k}-n^{2^k} will always be even, since both

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3 years ago
Help me with number 15 and 16
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Answer:

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Step-by-step explanation:

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