By applying the property of similar triangles, the distance Amana from point A to B walked is: B. 226 ft.
<h3>How to determine the distance?</h3>
By critically observing the diagram (see attachment), we can deduce that two (2) similar triangles were formed by the First Ave. and Second Ave.
By applying the property of similar triangles, the distance Amana walked is given by:
(AB + 113)/113 = (280 + 140)/140
(AB + 113)/113 = 420/140
(AB + 113)/113 = 3
AB + 113 = 3 × 113
AB + 113 = 339
AB = 339 - 113
AB = 226 ft.
Read more on similar triangles here: brainly.com/question/1518795
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Answer:
Step-by-step explanation:
-4x+5y≥-5
when y=0,-4x≥-5
x≤5/4
when x=0,5y≥-5
y≥-1
draw a line through (5/4,0) and (0,-1)
put x=0,y=0
0≥-5
therefore origin lies on the graph.
Answer:
(242) 969-0519
(338) 837-0798
(857) 705-0462
(251) 837-6638
(460) 208-1331
(412) 505-2184
Step-by-step explanation:
Class limits are the smallest and the largest data value that can go into a class.
Class marks are the midpoints of the classes. They are obtained by averaging the limits.
Cutpoints are<span> specified values used to sort continuous variables into discrete categories.
</span><span>Class Midpoint is the middle value of each data class.
For qualitative data, </span>c<span>utpoints and midpoints make sense, but class limits and marks do not, since qualitative data cannot be grouped using Limit grouping.
option D.
</span>
Answer:
the total surface of the box is 486 cm 2
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