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2 years ago

-4/4- (-8/4) Write answer as a decimal

1 answer:

8 0

-4/4 can be reduced to -2.
(-8/4) can be reduced to -1.
What you have to do next is to add -1-(-2).
The final answer is 1.
Hope that helps!!!.

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Keith’s high school played 4 football games this year, 2 of the games were played at night . He attended 3 games. How many footb

Nikitich [7]

Answer:

Step-by-step explanation:

because there were 4 games playes in total and he attended 3 of the 4 games so 4-3=1

4 0

3 years ago

3x+2y=3y-2 line 1 x+y=10 line 2 solve for x/y

GrogVix [38]

Answer:

x/y=1/4

Step-by-step explanation:

3x+2y=3y-2

3x=3y-2y-2

3x=y-2

y=3x+2

x+y=10

x+3x+2=10

4x+2=10

4x=10-2

4x=8

x=8/4

x=2

2+y=10

y=10-2

y=8

x/y=2/8=1/4

3 0

3 years ago

A phone plan costs $29.99 per month and includes 200 minutes of calling time. Minutes over 200 are charged at a rate of 25 cents

mylen [45]

Step-by-step explanation:

357-200 is 157 extra minutes (we are only counting the extra minutes)

157*0.25 is 39.25 (this is how much is the extra minutes in total cost)

therefore, add 39.25 and 29.99

29.99+39.25 is 62.24

Therefore, the total bill was $62.24

hope this helps :)

Have a nice day !

5 0

3 years ago

The music store sold 12 trumoets and 19 clarinets last month. If clariners sell for $139.95 and the store made $4,578.45 from sa

Kamila [148]

Answer:

$159.95

Step-by-step explanation:

Let price of trumphet be defined by $x$

price of clarinet = $139.95

Number of clarinets sold = 19

Earning through clarinets' sale = $19*139.95 = 2659.05$

Total earning of store = $4578.45

Earning through trumphets' sale = $4578.45 - 2659.05 = 1919.40$

price of one trumohet = $\frac{1919.40}{12} = 159.95$

price of clarinet = $159.95

7 0

3 years ago

goldfiish [28.3K]

Answer:

The volume of can A is half the volume of can B.

Step-by-step explanation:

Given

Can A and Can B

Required

The true statement

For Can A, we have:

$h =8$

$r = 0.5$

The volume is:

$Volume = \pi r^2h$

This gives:

$V_A = \pi * 0.5^2 * 8$

$V_A = \pi * 2$

$V_A = 2\pi$

For Can B, we have:

$h =4$

$r = 1$

The volume is:

$Volume = \pi r^2h$

This gives:

$V_B = \pi * 1^2 * 4$

$V_B = \pi * 4$

$V_B = 4\pi$

So, we have:

$V_A = 2\pi$

$V_B = 4\pi$

By comparison, (d) is correct

4 0

2 years ago