Using the given fractions,<span><span>2/3</span>÷<span>1/8
</span></span><span>Applying the </span>fractions formula for division,<span>=<span><span>2/3</span><span>×8/1</span></span></span><span><span>
</span></span>Simplifying 16/3,
the answer is<span>=5 <span>1/<span>3
So 6 is correct</span></span></span><span><span><span>
</span></span></span>
A force of 182.6 lb should be applied to lift 700 lb object.
<h3>How to calculate the force?</h3>
Let the force required to lift be F
Total length = 29 in.
Distance of short end from pivot = in.
Distance from long end = 29-6 = 23 in.
Now Equating moments
F × 23 = 700x6
23F = 4200
F = 4200/23
= 182.6 lb
A force of 182.6 lb should be applied to lift 700 lb object.
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Answer:
yeh you are correct so it will be b is equal to minus 42 minus 9.3 that will be equal to -51.3 so that is the value of b
