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Morgarella [4.7K]
3 years ago
5

lass="latex-formula">
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
6 0

Answer:

That equals 22π

Step-by-step explanation:

hope this helps

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The quotient of five and seven
Gala2k [10]

Answer:

Decimal: 0.71428571428

Fraction: 5/7

Step-by-step explanation:

Quotient is just the result of a division problem so 5 and 7: 5/7

Decimal: 0.71428571428

Fraction: 5/7

7 0
4 years ago
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Is it possible for a system to have more than one solution? Explain your answer
Anastasy [175]
A linear system can have infinite solutions if both systems represent the same line. if a linear system down not represent the same line then it can only have one or no solutions. No solution is if the system is representing parallel lines and one solution represents an intersection of the two lines.  in a nonlinear system you can have infinite or up to a maximum of intersections as the highest degree of the systems.
7 0
3 years ago
If someone help me that be awesome
nevsk [136]
The answer is 12,600,000... hope this helps any :3
4 0
4 years ago
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Is this answer to the question correct?
Dmitrij [34]

Answer:

y is correct but x is not

Step-by-step explanation:

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3 0
3 years ago
Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $
nlexa [21]

Answer:

<em>$4.84</em>

<em></em>

Step-by-step explanation:

Given that

For delivery within 1\frac{1}2 mi, charges = $1.25

For delivery within 1\frac{1}2 mi - 1\frac{3}4 mi, charges = $1.70

For delivery within 1\frac{3}4 mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2\frac{1}4 mi, charges = $2.60

For delivery within 2\frac{1}4 mi - 2\frac{1}2 mi, charges = $3.05

For delivery within 2\frac{1}2 mi - 2\frac{3}4 mi, charges = $3.50

For delivery within 2\frac{3}4 mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3\frac{1}4 mi, charges = $4.40

So, every 0.25 mi or \frac{1}4 mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.

The distance of 3\frac{1}8 miles lies within the range 3 mi - 3\frac{1}4 mi.

So actual charges after increase of 10%

\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}

6 0
3 years ago
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