answer it its a easy pionts no links or ill report u and u will not get brianly anymore pease answer it plsssss

Mathematics

1 answer:

Norma-Jean [14]2 years ago

6 0

Answer:

8:112 third blank put 14

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74y−8−78y=−4y−8 how many solutions

Vera_Pavlovna [14]

Answer:

there is an infinet amount of answers.

Step-by-step explanation:

4 0

3 years ago

A card is chosen at random from a deck of 24 cards, 4 red, 8 black, 6 blue, and 6 green.

stira [4]

The color of the card should be “Red.”

3 0

3 years ago

Find the domain and range of the relation: (-8,8),(-8,7),(-8,6),(-8,5). Then determine whether the relation is a function.

Andrej [43]

The domain is {-8}
The range is {5,6,7,8}
The relation is not a function as the domain value -8 maps to multiple values. All domain values in a relation needs to map to exactly one range value for it be a function.

8 0

3 years ago

The midpoint of AB is at (3,7) and A is at (0,-5). Where is B located?

olga nikolaevna [1]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
% (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\qquad thus
\\
----------------------------\\$ $\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ 0}}\quad ,&{{ -5}})\quad 
% (c,d)
B&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
(3,7)\impliedby midpoint\qquad thus
\\ \quad \\
\left(\cfrac{{{ x_2 }} + {{ 0}}}{2}=3\quad ,\quad \cfrac{{{ y_2 }} + {{( -5)}}}{2}=7 \right)\to 
\begin{cases}
\cfrac{{{ x_2 }} + {{ 0}}}{2}=3
\\ \quad \\
\cfrac{{{ y_2 }} + {{ -5}}}{2}=7
\end{cases}
\\ \quad \\
solve\ for\ x_2\ and\ y_2$

3 0

3 years ago

Use the quadratic formula to solve x2+7x+3. Show all of your work. Then describe the solution.

Mariana [72]

Answer:

Step-by-step explanation:

The coefficients of the quadratic x^2 + 7x + 3 are a = 1, b = 7 and c = 3.

The discriminant is b^2 - 4ac, or 49 - 4(1)(3), or 49-12, or 37.

Because the discriminant is positive, we know that this quadratic equation has two real, different solutions.

-7 ± √37

x = --------------- => x = (-7 + √37)/2 and x = (-7 - √37)/2

In words: This quadratic equation has two real, unequal solutions involving the radicand 37.

7 0

3 years ago

answer it its a easy pionts no links or ill report u and u will not get brianly anymore pease answer it plsssss​

answer it its a easy pionts no links or ill report u and u will not get brianly anymore pease answer it plsssss